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2 years ago

8

A grower packs 4,568 peaches. He packs the most peaches possible, dividing them equally into 9 boxes, and then gives away the re

maining peaches.
How many peaches are in each box.
How many peaches does he give away.
If he sells 7 boxes, how many peaches does he have left.

2 answers:

8_murik_8 [283]2 years ago

5 0

507 peaches in each box

He gives away 5 peaches

If he’s sells 7 boxes he’ll have 1014 peaches left

KiRa [710]2 years ago

3 0

507 peaches in each box.

He gives away 5 peaches.

If he sells 7 boxes he has 1019 peaches left.

Hope this helps.

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3 years ago

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(a) For using Cramer's rule you need to find matrix $A$ and the matrix $B_j$ for each variable. The matrix $A$ is formed with the coefficients of the variables in the system. The first step is to accommodate the equations, one under the other, to get $A$ more easily.

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In the case of B2, the determinant is going to be zero. Instead of using the rule, substitute the values of the variable $x_1$ in one of the equations and solve for $x_2$ :

$2x_1+5x_2=1\\2(-2)+5x_2=1\\-4+5x_2=1\\5x_2=1+4\\ 5x_2=5\\x_2=1$

(b) In this system, follow the same steps,ust remember $B_3$ is formed by replacing the 3rd column of A with the results of the equations:

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$B_2=\left[\begin{array}{ccc}2&1&0\\1&0&1\\0&0&2\end{array}\right]$

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3 years ago

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3 years ago

Read 2 more answers

How much material is needed to construct a triangular tent that is 6 feet wide 4 feet tall and 8 feet long with side measurement

jonny [76]

Answer: 152ft^2

The amount of material needed to construct the tent is 152ft^2

Step-by-step explanation:

The amount of material needed to construct a triangular tent= the surface area of the triangular tent.

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S.A = Ab + At + Ar ....1

Area of the base Ab= Length × width = 8×6 = 48ft^2

Area of the two triangles At = 2 × 0.5 × width × height

At = width × height = 6×4 = 24ft^2

Area of the two rectangles Ar = 2 × side measurement × length

Side measurement is given as 5ft.

or it can be calculated using;

Side length can be calculated using Pythagoras theorem.

Examining the figure attached, we can see that;

Side breadth b = √(h^2 + (w/2)^2)

b = √(4^2 + (6/2)^2) = √(16+9) = √25

b = 5ft

Ar = 2×5×8 = 80ft^2

From eqn1, S.A can be solved as;

S.A = 48 + 24 + 80

S.A = 152ft^2

7 0

4 years ago