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prisoha [69]
2 years ago
8

A grower packs 4,568 peaches. He packs the most peaches possible, dividing them equally into 9 boxes, and then gives away the re

maining peaches.
How many peaches are in each box.
How many peaches does he give away.
If he sells 7 boxes, how many peaches does he have left.
Mathematics
2 answers:
8_murik_8 [283]2 years ago
5 0
507 peaches in each box

He gives away 5 peaches

If he’s sells 7 boxes he’ll have 1014 peaches left
KiRa [710]2 years ago
3 0

507 peaches in each box.

He gives away 5 peaches.

If he sells 7 boxes he has 1019 peaches left.

Hope this helps.

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Answer:

DB = CA (Proved)

Step-by-step explanation:

Statement 1.

∠D = ∠C, M is the midpoint of DC and ∠1 = ∠2

Reason 1.  

Given

Statement 2.

Between Δ DBM and Δ CAM,  

(i) DM = CM,

(ii) ∠D = ∠C  and  

(iii) ∠DMB = ∠CMA

Reason 2.

(i) given  

(ii) given and  

(iii) ∠ DMB = ∠1 + ∠AMB and  ∠CMA = ∠2 + ∠AMB

Since ∠1 = ∠2, so, ∠DMB = ∠CMA.

Statement 3.

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Reason 3.

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Statement 4.

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egoroff_w [7]
<h2>Explanation:</h2><h2></h2>

Here you haven't provided any function, so I'll assume this one:

f(x)=3x^2-18x+33

This is a quadratic function whose graph represents a parabola. Any parabola has its vertex at the point:

V(x,y) \\ \\ \\ x=-\frac{b}{2a} \\ \\ y=f(-\frac{b}{2a}) \\ \\ \\ where: \\ \\ \\ f(x)=ax^2+bx+c \\ \\ \\ So: \\ \\ a=3 \\ \\ b=-18 \\ \\ c=33

Therefore:

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\boxed{V(3,6)}

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Answer:

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Answer:

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62.5*100=6250

8 0
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Read 2 more answers
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