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Svet_ta [14]
3 years ago
11

(9u+w)^2 (use foil).................

Mathematics
1 answer:
Yanka [14]3 years ago
8 0

Answer:

Step-by-step explanation:

(9u + w)(9u + w)

f: 9u * 9u = 81 u^2

o: 9u * w

i: 9u* w

l: w * w = w^2

Result

81u^2 + 9uw + 9uw + w^2

81u^2 + 18uw + w^2

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PLEASE HELP SO I CAN GET THIS OVER WITH!!! WILL GIVE BRAINLIEST!!!!
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Her first visit and follow up 60 mins + 30 mins

The limit is 8 follow ups per day

The hospital has 8 hrs available for appointments

Her first visit cost $120 (60 mins) as her follow up was $70 (30 mins)

X = Visits

Y = Follow-ups

And since her first visit and follow up equals to an hour and 30 mins, meaning for it to all add up into the 8 hrs for the appointment, it'll be... 1 hr, 30 mins/ 3 hrs/ 4 hrs, 30 mins/ 6 hrs/ 7 hrs, 30 mins/ <em>9 hrs</em>

Eight hours is the limit so that means it equals to 5 visits and 6 follow ups, due to if you want it to be the whole 8 hours.

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3 years ago
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So, Sorry if this seems long but I missed a week of school due to the flu and I need help on this math homework. 9th grade Algeb
marissa [1.9K]
The first one is x=-1
The second one is b=1
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8 0
3 years ago
The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1700 vot
lara [203]

Answer:

z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562  

p_v =P(z>2.562)=0.0052  

So the p value obtained was a very low value and using the significance level given \alpha=0.02 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

Step-by-step explanation:

Data given and notation

n=1700 represent the random sample taken

\hat p=0.66 estimated proportion of voters that favored construction

p_o=0.63 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that percentage of residents who favor construction is more than 63%.:  

Null hypothesis:p \leq 0.63  

Alternative hypothesis:p > 0.63  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.562)=0.0052  

So the p value obtained was a very low value and using the significance level given \alpha=0.02 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

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3 years ago
How many fifths are there in 8 3/5?​
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Answer:

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Step-by-step explanation:

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A shape is shown on the graph:
Setler79 [48]
Sorry it took me so long, the correct answer is B.
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