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olganol [36]
3 years ago
8

Any tall single gothic girls

Advanced Placement (AP)
2 answers:
zheka24 [161]3 years ago
8 0

Answer:

Well I'm tall and single but I'm not Gothic

Explanation:

And I'm not looking to date anyone either...

But we can be friends if you want

Sergeeva-Olga [200]3 years ago
7 0

Answer:

Explanation:

This is not any dating sight go one something else if you looking for some gothic girls.

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Which function is an extended function
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Answer:

D. The last option

Explanation:

You can't divide by 0, so find out when the given function is discontinuous.

\frac{x^3+3x^2-x-3}{x^2-1} =\frac{x^3+3x^2-x-3}{(x+1)(x-1)}

You can see that x is discontinuous at x=-1,1, so find a piecewise function that fill in those gaps.

Plug x=-1,1 into your function to find out what values you need to fill in. But of course it's discontinuous at those points, so plug in a number near x=1 and x=-1. I chose x=-1.1 and x=1.1

f(-1.1)\frac{(-1.1)^3+3(-1.1)^2-(-1.1)-3}{(-1.1)^-1} = 1.9 \approx 2

f(1.1)\frac{(1.1)^3+3(1.1)^2-(1.1)-3}{(1.1)^-1} = 4.1 \approx 4

so we need to fill in 2 at x=-1, and fill in 4 at x=1

6 0
3 years ago
If ƒ(x )= 2x 2 3, then ƒ(x - 1)= 2x 2 4x 5. true or false
nalin [4]
Since you didn't write the signs, I have to make some suggestions, this is what I assume:
<span>If ƒ(x )= 2x²+3, then ƒ(x - 1)= 2x²+4x+5.

So, how much is </span><span>ƒ(x-1?)

it would be= 2(x-1)²+3=</span>2(x-1)<span>(x-1)+3=</span>2(x²-2<span>x+1)+3=</span>2x²-4x+2+3=2x²-4<span>x+5

So, yes, if my assumption is correct, then it's true!

</span>




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The purpose of creating a practice outline is to
nadya68 [22]
It's B. Organize and learn information.

My nama jeff. ;)

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It is a symbol for a value that you don't know yet it is commonly written as a letter for example x or y.

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