2 years ago

Can someone help me with both of these

Mathematics

1 answer:

telo118 [61]2 years ago

3 0

Answer:

shrek

Step-by-step explanation:

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-1/13-10/39 in lowest terms

Ira Lisetskai [31]

Step-by-step explanation:

the answer is already as simplified as it could be

8 0

3 years ago

How much of the initial mass remains after 80 years? (Round your answer to three decimal places.)

aleksandr82 [10.1K]

Given

$y=11(\frac{1}{2})^{\frac{t}{30}}$

When t = 80

We substitute for t

$y=11(\frac{1}{2})\frac{}{}^{\frac{80}{30}}$

Simplify

$y=11(\frac{1}{2})^{\frac{8}{3}}$

Simplify further

$y=1.732g$

The final answer

4 0

1 year ago

The value of a car after t years can be found using the formula V = C(1 - r)t, where V is the current value of the car, C is the

Stells [14]

The given formula is
$V = C(1-r)^{t}$

Therefore
$(1-r)^{t} = \frac{V}{C} \\\\ 1-r = ( \frac{V}{C} )^{1/t} \\\\ r = 1 - ( \frac{V}{C} )^{1/t}$

Given:
C = $25,000
V = $12,000
t = 4.5 years

C/V = 0.48
1/t = 0.2222
Therefore
$r = 1 - 0.48^{0.2222} = 0.1505 = 15.05\%$

Answer: 15% (nearest integer)

8 0

3 years ago

1/2(x+4)=-12 help me please

skad [1K]

1/2(x + 4) = -12

1/2x + 2 = -12

1/2x = -10

x = -20

5 0

3 years ago

It took the high school hockey team 5h to travel to a tournament in Thunder Bay. They travelled by bus and plane a total distanc

mote1985 [20]

Entire distance = 1,320
Entire time = 5 hours

bus avg = 40 km/h
plane avg = 600 km/h

Working this by trial and error
1 hour bus 4 hour plane = 40 + 2,400 = 2,800 distance (too high)
2 hour bus 3 hour plane = 80 + 1,800 = 1,880 distance (too high)
3 hour bus 2 hour plane = 120 + 1,200 = 1,320 distance (Correct!!)

So, they traveled 3 hours by bus and 2 hours by plane
(yes, you had the right answer).

8 0

2 years ago