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MA_775_DIABLO [31]
3 years ago
6

A 400-kg box is lifted vertically upward with constant velocity by means of two cables pulling at 40. 0° on either side of the v

ertical direction. What is the tension in each cable?.
SAT
1 answer:
amm18123 years ago
7 0

Answer:

2558 N.

Explanation:Each rope takes half, so the vertical component of the force on each rope is half of this, or 1960 N.. But they are pulling at a 40 degree angle, so if t is the tension then t*cos(40) = 1960. This gives t = 2558 N.

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<h3>Writting the code in python:</h3>

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<em>def __init__(self,key):</em>

<em>self.left = None</em>

<em>self.right = None</em>

<em>self.val = key</em>

<em>self.parent = None</em>

<em>class MinHeap:</em>

<em>def __init__(self, maxsize):</em>

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<em>self.Heap = Node(-1 * sys.maxsize )</em>

<em>self.FRONT = self.Heap</em>

<em># A utility function to do inorder tree traversal</em>

<em>def isLeaf(self, node):</em>

<em>if node.left == None and node.right == Node:</em>

<em>return True</em>

<em>return False</em>

<em># Function to swap two nodes of the heap</em>

<em>def swap(self, node1, node2):</em>

<em>node1.data, node2.data = node2.data, node1.data</em>

<em># Function to heapify the node at pos</em>

<em>def minHeapify(self, node):</em>

<em># If the node is a non-leaf node and greater</em>

<em># than any of its child</em>

<em>if not self.isLeaf(node):</em>

<em>if (node.data > node.left.data or</em>

<em>node.data > node.right.data):</em>

<em># Swap with the left child and heapify</em>

<em># the left child</em>

<em>if node.left.data < node.right.data:</em>

<em>self.swap(node, node.left)</em>

<em>self.minHeapify(node.left)</em>

<em># Swap with the right child and heapify</em>

<em># the right child</em>

<em>else:</em>

<em>self.swap(node, node.right)</em>

<em>self.minHeapify(node.right)</em>

<em># Function to insert a node into the heap</em>

<em>def insert(self, element):</em>

<em>if self.size >= self.maxsize :</em>

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<em>self.size+= 1</em>

<em>self.bst_insert(FRONT, element)</em>

<em>current = FRONT</em>

<em>while current.parent != None and current.data < current.parent.data:</em>

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<em>current = current.parent</em>

<em># Function to print the contents of the heap</em>

<em>def Print(self):</em>

<em>self.inorder()</em>

<em># Function to build the min heap using</em>

<em># the minHeapify function</em>

<em>def inorder(self, root):</em>

<em>if root:</em>

<em>inorder(root.left)</em>

<em>print(root.val)</em>

<em>inorder(root.right)</em>

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<em>if root is None:</em>

<em>root = node</em>

<em>else:</em>

<em>root.next = node</em>

<em>self.FRONT = node</em>

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<em>minHeap.insert(3)</em>

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<em>minHeap.minHeap()</em>

<em>minHeap.Print()</em>

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See more about python at brainly.com/question/13437928

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