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Brrunno [24]
3 years ago
10

A) Given mZBYC = 107°, ZDBC = 43°, mZDBA = 80° mZBCA =

Mathematics
1 answer:
Paul [167]3 years ago
7 0

Answer:

a po sana makatulong

Step-by-step explanation:

sana makatulong sainyu

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Simplify <br> 1+sinx/cosx+cosx/1+sinx
Dmitry [639]
\frac{1 + sin(x)}{cos(x)} + \frac{cos(x)}{1 + sin(x)}
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\frac{1 + 2sin(x) + sin^{2}(x)}{cos(x)[1 + sin(x)]} + \frac{cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x) + cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + 1}{cos(x)[1 + sin(x)]}
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6 0
3 years ago
Which of the following statements best describes the graph of -5x+2y=1
ahrayia [7]
The answer is the third option.
x and y are both to the first degree so we know it makes a straight line.
Next check the ordered pairs to see which set are true in the equation.
3 0
4 years ago
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What is the equation in slope-intercept form of the line that passes through the points(-4,2) and (12,6)?
aleksandrvk [35]

Answer:

y=1/4x+3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(6-2)/(12-(-4))=4/(12+4)=4/16=1/4

y-y1=m(x-x1)

y-2=1/4(x-(-4))

y-2=1/4(x+4)

y=1/4x+4/4+2

y=1/4x+1+2

y=1/4x+3

3 0
3 years ago
Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (
Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that I=\int_0^3 x^3-4x dx=9/4. We use the properties of integrals to write the new integrals in terms of I.

A) \int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2. We have used that ∫cf dx=c∫f dx.

B) \int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4. Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

4 0
3 years ago
What inequality is graphed below?
vovikov84 [41]

Answer:

X>-6

Step-by-step explanation:

That's the answer.....

7 0
3 years ago
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