PLEASE HELP! NEED IT NOW!

How quickly do synthetic fabrics such as polyester decay in landfills? A researcher buried polyester strips in thes oil for diff

ad-work [718]

Answer:

no enough evidence to draw up a conclusion

Step-by-step explanation:

Data:

let: $\mu _{1}$ = decay after 2 weeks

$\mu _{2}$ = decay after 16 weeks

Making the hypotheses:

Null hypothesis; $H_{o} = \mu _{1} - \mu _{2} = 0$

the deviation = 0.05

the standard difference = 4

Conditions:

The normal distribution curve can be plotted on a graph and the plot shows that the distribution is a skewed distribution.

Then,

$t = \frac{(123.8-16.4)-0}{\sqrt{\frac{4.6^{2} }{5}+\frac{16.09^{2} }{5} } } \\ = 0.989$

Therefore, it can be concluded that 0.1983 > 0.05. This presents our failure to reject the null hypothesis.

Thus, there is not enough evidence to conclude that polyester decays more in less than 2 weeks.

5 0

3 years ago

A bag contains 56 marbles ,some red ,some yellow ,some blue,there are half as many red as blue and eight more yellow than red .h

Delicious77 [7]

Let red marbles be x.

Blue : 2x
Red : x
Yellow : x+8

2x + x + x + 8 = 56
4x = 48
x = 12

Red marbles: 12
Blue : 24
Yellow: 20

7 0

3 years ago

Find the points on the cone z2 = x2 + y2 that are closest to the point (6, 2, 0).

aliya0001 [1]

Answer:

The closest points on the cone are;

(6, 2, -√10) and (6, 2, √10)

Step-by-step explanation:

Let B(x, y, z) denote a point on the cone.

Therefore, the distance between the points (6, 2, 0) and B(x, y, z) is;

d = √[(x - 6)² + (y - 2)² + (z - 0)²]

d = √[(x - 6)² + (y - 2)² + z²]

Since we are given that z² = x² + y², we now have;

d = √[(x - 6)² + (y - 2)² + x² + y²]

Taking the square of both sides gives;

d² = [(x - 6)² + (y - 2)² + x² + y²]

x² is an increasing function. Thus, minimizing d is also the same as to minimize f (x, y) = d²

Thus, f' = 0. So;

df/dx = 2(x - 6) + 2x = 0

2x - 12 + 2x = 0

4x = 12

x = 12/4

x = 3

Similarly,

df/dy = 2(y - 2) + 2y = 0

2y - 4 + 2y = 0

4y - 4 = 0

4y = 4

y = 4/4

y = 1

Now,from earlier;

z² = x² + y²

Thus;

z = ±√(3² + 1²)

z = ±√10

Thus, the closest points on the cone are;

(6, 2, -√10) and (6, 2, √10)

7 0

3 years ago

Please help me i really need help please help please

solong [7]

Answer:

3.605 ft is the answer.

Step-by-step explanation:

Applying Pythagoras theorem,

a^2 + b^2 = c^2

2^2 + 3^2 = c^2

4 + 9 = c^2

13 = c^2

3.605 = c

therefore, the answer is 3.605.

:)

8 0

2 years ago

The diameter of a circle is 23 inches and the circle has two chords of length 14 inches what is the distance from each chord to

Svetradugi [14.3K]

Answer:

9.12 + 9.12 = 18.24 inches

Step-by-step explanation:

Diameter = 23 inches (given)

Radius = 11.5 inches

2 Chords of length = 14 inches ( You didn't specify if the 14 inches is for both chords or for a single cord. I'll assume it's for two cords 14 and 14inches apart.

To clearly solve this, we'll make some mild assumptions.

Let the perpendicular distance of the chords from the center of the circle to represented as " x and y"

Therefore:

x^2 + 7^2 = 11.5 ^ 2

x^2 + 49 = 132.25

x^2 = 132.25 - 49

x^2 = 83.25

x = √ 83.25

x = 9.12 inches

Since the cords have thesame length (Assumed from the way the question was structured, the distance would still be thesame)

y^2 + 7^2 = 11.5 ^ 2

y^2 + 49 = 132.25

y^2 = 132.25 - 49

y^2 = 83.25

y = √ 83.25

y = 9.12 inches

Therefore, the distance will be :

9.12 + 9.12 = 18.24 inches

Have fun!

6 0

3 years ago