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Goshia [24]
3 years ago
14

Nxveah_jruciee banna

Mathematics
1 answer:
Sophie [7]3 years ago
6 0

Answer:

Ok...

Step-by-step explanation:

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Find CD if C(0,3) and D(4,7)
MakcuM [25]
C(0,3) \\
x_1=0 \\
y_1=3 \\ \\
D(4,7) \\
x_2=4 \\
y_2=7 \\ \\
\overset{\underline{\ \ \ \ }}{CD} =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(4-0)^2+(7-3)^2}= \\
=\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{16 \times 2}=4\sqrt{2} \\ \\
\boxed{\overset{\underline{\ \ \ \ }}{CD} = 4\sqrt{2}}
7 0
3 years ago
I really need Help with this equation Please!!!!
Slav-nsk [51]

Answer:

Option D:  - 6;  $ \textbf{-5}\frac{\textbf{5}}{\textbf{2}} $;   $ \textbf{-4}\frac{\textbf{1}}{\textbf{5}} $.

Step-by-step explanation:

The sequence is defined by:

$ A(n) = -6 + (n - 1)\bigg( \frac{1}{5} \bigg ) $

To find the first term of the sequence simply substitute n = 1.

First term of the sequence:

$ A(1) = -6 + (1 - 1)\bigg( \frac{1}{5} \bigg ) $

        $ = - 6 $

Fourth term of the sequence:

$ A(2) = -6 + (4 - 1) \bigg ( \frac{1}{5} \bigg) $

        $ = - 6 + 3\bigg( \frac{1}{5} \bigg) $

        $ = \frac{- 30 + 3}{5} $

        $ = \frac{-27}{5} $

        $ = \frac{-25 - 2}{5} $

        $ = - 5 - \frac{2}{5} $

        $ = -5\frac{2}{5} $   is the required answer.

Tenth term of the sequence:

$ A(10) = - 6 + (10 - 1) \bigg( \frac{1}{5} \bigg) $

         $ = - 6 + 9\bigg( \frac{1}{5} \bigg) $

         $ = \frac{-30 + 9}{5} $

         $ = \frac{-21}{5} $

         $ = \frac{-20 - 1}{5} $

         $ = - 4 - \frac{1}{5} $

         $ = -4\frac{1}{5} $  is the required answer.

       

       

3 0
4 years ago
*100 POINTS*
Mice21 [21]

Answer:

y= -2/1x -4

Step-by-step explanation:

Hope it helped!

5 0
3 years ago
Read 2 more answers
Simplify <br> 4(1 + 9x) thank you
Rufina [12.5K]

Answer:

4+36x

Step-by-step explanation:

you multiply the number on the outside of the parentheses with the numbers in the inside of the parentheses.

4 times 1 = 4

4 times 9x = 36x

36x+4

7 0
3 years ago
7(y+x)−2(x−y)=−2
tangare [24]
The answer is y=9/5x-31

6 0
3 years ago
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