What is the constant rate of change for this equation y = 1/9x-20 ?
2 answers:
Answer: The constant rate change would be .
Step-by-step explanation: The general rate of change can be found by using the difference quotient formula. To find the average rate of change over an interval, enter a function with an interval: f (x) = , [2,3]
Write y = x - 20 as a function which is f (x) =
x - 20
Consider the difference quotient formula which is .
Find the components of the definition. simplify then it would be
.
Lastly plug in all the components.
After solving all this the answer would be
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Answer:
(C) Perpendicular bisector theorem
Step-by-step explanation:
(A) Right angle theorem : The right angle theorem states that if two angles are supplementary and congruent, then these two angles are right angles.
(B) Converse of perpendicular bisector theorem: The converse of perpendicular bisector theorem states that If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of that segment.
(C) Perpendicular Bisector Theorem: The Perpendicular Bisector Theorem states that If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.
(D) Pythagorean theorem: The Pythagorean theorem states that in the right angled triangle, the square of the hypotenuse of the triangle is equal to the sum of the squares of the other two sides that is:
Since, the given statement is the statement of the Perpendicular bisector theorem, thus option C is correct.