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2 years ago

What is the missing length?

Mathematics

2 answers:

dsp732 years ago

6 0

11.7

…………………………………………………..

vovangra [49]2 years ago

6 0

Answer:

11.7

Step-by-step explanation:

This shape is a rectangle.

Given,

Length ( l ) = 9 m

Breadth ( b ) = u

Area = 105.3 m²

To find : u = ?

Formula : -

Area of the rectangle = lb

105.3 = 9 x b

b = 105.3 / 9

b = 11.7

b = u = 11.7 meters

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Part 1: Write mathematical equations of sinusoids.

Ilya [14]

Answer:

Part 1: Write mathematical equations of sinusoids.

1. The following sinusoid is plotted below. Complete the following steps to model the curve using the cosine function.

a) What is the phase shift, c, of this curve? (2 points)

b) What is the vertical shift, d, of this curve? (2 points)

c) What is the amplitude, a, of this curve? (2 points)

d) What is the period and the frequency factor, b, of this curve? (2 points

e) Write an equation using the cosine function that models this data set. (5 points)

2. The following points are a minimum and a maximum of a sinusoid. Complete the following steps to

model the curve using the sine function

Step-by-step explanation:

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5 0

2 years ago

Help~~~~~~~~~~~~~~~~~~~~~~~~~

igor_vitrenko [27]

Answer:

28.25 square units

Step-by-step explanation:

A circumference of the circle is

$C=2\pi r,$

where r is the radius of the circle.

So,

$18.84=2\pi r\\ \\r=\dfrac{18.84}{2\pi}=\dfrac{9.42}{\pi}\ cm$

The area of the circle is

$A=\pi r^2$

Substitute the value of the radius:

$A=\pi \cdot \left(\dfrac{9.42}{\pi}\right)^2=\dfrac{9.42^2}{\pi}\approx 28.25\ un^2$

8 0

3 years ago

Read 2 more answers

What is 8x over 2y ?

Nana76 [90]

Answer:

6 2/3.. i think

Step-by-step explanation:

hopefully u understand my messy handwriting

4 0

2 years ago

for every three short horned lizards there are two fence lizards. If there are 54 short horned lizards how many fence lizards ar

Komok [63]

Answer: 36

Step-by-step explanation:

54/3 = 18 x 2 = 36

8 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

3 years ago