(A) Y= 2x+3
(B) Y= -x+6
(C) Independent. They are two distinct non-parallel lines that cross at one point.
here are A,B,& C not to sure about D
Answer: y = 1.2x + 1.4
Step-by-step explanation:
1. Write down the coordinates of the first point. Let's assume it is a point with x₁ = -2and y₁ = -1.
2. Write down the coordinates of the second point as well. Let's take a point with x₂ = 3 and y₂ = 5.
3. Use the slope intercept formula to find the slope:
m = (y₂ - y₁)/(x₂ - x₁) = (5-1)/(3-2) = 4/1 = 1.2
4. Calculate the y-intercept. You can also use x₂ and y₂ instead of x₁ and y₁ here.
b = y₁ - m * x₁ = -1 - 1.2*-2 = 1.4
5. Put all these values together to construct the slope intercept form of a linear equation:
y = 1.2x + 1.4
D. If I told you to walk 1 metre or 100cm you would have walked the same distance but more cm as the ratio of cm:m is 100:1, this is the same thing for surface area except the ratio is 1000:1
Answer: d
²+ c
−
4
d
+
4
Step-by-step explanation:
Simplify the expression.
d
²+
2
c
−
4
d
+
4
d
²+ c
−
4
d
+
4
Answer:
equations 1, 2, 6 . . . (top two, bottom right)
Step-by-step explanation:
For the standard-form equation of an ellipse:
Ax^2 +Bx +Cy^2 +Dy +E = 0
we can define ...
p = min(A, C)
q = max(A, C)
Then the eccentricity can be shown to be ...
e = √(1 -p/q)
p/q = 1 -e^2
For eccentricity < 0.5, we want ...
p/q > 3/4
__
Checking the values of p/q for the given equations left-to-right, top-to-bottom, we have p/q = ...
- 49/64 ≈ 0.765 . . . e < 0.5
- 81/100 ≈ 0.810 . . . e < 0.5
- 6/54 ≈ 0.111 . . . e > 0.5
- 36/49 ≈ 0.734 . . . e > 0.5
- 4/25 ≈ 0.160 . . . e > 0.5
- 64/81 ≈ 0.790 . . . e < 0.5
Equations 1, 2, 6 are of ellipses with eccentricity < 0.5.