Combine like terms in Qx + 12 = 13x + P:
x(Q-13) = P-12
P-12
Then x = ----------
Q-13
Note that Q may not = 13. But none of the answer choices present Q = 13.
Let's go thru the answer choices one by one.
P-12
x = ----------
Q-13
-24
Check out A: Q=12 and P= -12: x = -------- = 24 This is OK (ONE sol'n)
-1
-25
Check out B: Q = -13 and P = -13: x = ----------- = 25/26 OK
-26
13-12
Check out C: Q = -13 and P = 13: x = ------------ = -1/26 OK
-13-13
12-12
Check out D: Q = 12 and P = 12: x= ---------- = 0 OK
12-13
It appears that in all four cases, the equation has ONE solution.
Line C.... I think..... Sorry if I’m wrong
Answer:
Step-by-step explanation:
The shape of this graph is that of a parabola. In this case the parabola opens down. The general form of the equation of such a parabola is
y = a(x - h)^2 + k, where (h, k) is the vertex and a is a coefficient to be determined.
In this particular case we can obtain the coordinates of the vertex (h, k) from the graph. They are (3, 4). Thus, h = 3 and k = 4. The graph goes through (1.5, 0). Use this information to determine the value of the coefficient a:
Then the equation of this parabola must be y = a(x - 3)^2 + 4.
0 = a(1.5 - 3)^2 + 4
Then:
0 = a(-1.5)^2 + 4, or
0 = 2.25a + 4, or
2.25a = -4, or
a = 16/9
Thus, the final result: The equation of this parabola is
y = (16/9)(x - 3)^2 + 4
whose graph is a parabola that opens down and has vertex (3, 4).
When you factor the parabola you get
(x+6)(x-2)
set each of these equal to zero
x+6=0 x-2=0
solve for x
x=-6 x=2
these are your x-intercepts
(-6,0) and (2,0)
Answer:hmm I don’t fully understand what you mean because there is no bottom of the number line it started at zero so all you have to do is fill the line in.
Step-by-step explanation:
