Question

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate).
4 sin(2θ) − 2 sin(θ) = 0

Answer 1

Answer:

θ = πk, 1.318+2πk, 4.965+2πk

Step-by-step explanation:

4sin(2θ) − 2sin(θ) = 0

8sin(θ)cos(θ) - 2sin(θ) = 0

2sin(θ)[4cos(θ)-1] = 0

2sin(θ) = 0

sin(θ) = 0

θ = πk

4cos(θ)-1 = 0

4cos(θ) = 1

cos(θ) = 1/4

θ ≈ 1.318+2πk, 4.965+2πk

Therefore, θ = πk, 1.318+2πk, 4.965+2πk