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3 years ago

What is the product? (Y^2+3Y+7)(8y^2+y+1

Mathematics

2 answers:

Luba_88 [7]3 years ago

6 0

Answer:

8y⁴+25y³+60y²+10y+7

Step-by-step explanation:

8y⁴+y³+y²+24y³+3y²+3y+56y²+7y+7

8y⁴+25y³+60y²+10y+7

belka [17]3 years ago

4 0

Answer:

8y^4+25y^3+60y^2+10y+7

Step-by-step explanation:

(y^2+3y+7)(8y^2+y+1)

We are going to multiply the first term, y^2, by the whole second part (8y^2+y+1)

8y^4+y^3+y^2

now we multiply the 2nd term, 3y, by the whole second part (8y^2+y+1))

24y^3+3y^2+3y

now we do the same to the last term, 7.

56y^2+7y+7

now we need to add all three of our products together

(8y^4+y^3+y^2)+(24y^3+3y^2+3y)+(56y^2+7y+7)

adding like terms:

8y^4+y^3+24y^3+y^2+3y^2+56y^2+3y+7y+7

we get:

8y^4+25y^3+60y^2+10y+7

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3 years ago

What is the product? (Y^2+3Y+7)(8y^2+y+1​

What is the product? (Y^2+3Y+7)(8y^2+y+1