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3 years ago

Please help meeeeeeeeeeeeeeee

Mathematics

1 answer:

NikAS [45]3 years ago

4 0

The answer is 81 :)

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Convert 3/20 to a percent.

inessss [21]

15% because 20 to 100, you have to multiply by five and what you do to the denominator, you do to the numerator
3*5=15
so the answer is 15/100 or 15%

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3 years ago

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Mr. King is considering a new job. He and his wife sit down to create a list of their monthly expenses, as shown in the table be

Sidana [21]

Answer:42,500

Step-by-step explanation: my teacher gave answer not sure how to get it though

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3 years ago

Can someone help me please!!!!!

deff fn [24]

Answer:

a) 5 banners

b) 2 banners

3) 2 banners

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Step-by-step explanation:

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3 years ago

Are these calculations correct? If so, please put in descending order:

Mkey [24]

No because the last one is not correct and if you want to text me back if you won't me to do it for you for the first three you can

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3 years ago

Determine an expression for dy<br> dx given that x = sin3<br> (t)andy = cos3<br> (t)

shtirl [24]

Answer:

$\frac{dy}{dx} =-\sqrt[3]{\frac{y}{x} }$

Step-by-step explanation:

Recall that using the chain rule we can state:

$\frac{dy}{dt} =\frac{dy}{dx}*\frac{dx}{dt}$

and therefore solve for dy/dx as long as dx/dt is different from zero.

Then we find dy/dt and dx/dt,

Given that

$x=sin^3(t)\\dx/dt = 3 sin^2(t)* cos(t)$

And similarly:

$y=cos^3(t)\\dy/dt=-3\,cos^2(t)*sin(t)$

Therefore, dy/dx can be determined by the quotient of the expressions we just found:

$\frac{dy}{dx} =\frac{dy/dt}{dx/dt} =\frac{-3\,cos^2(t)*sin(t)}{3\,sin^2(t)*cos(t)} =-\frac{cos(t)}{sin(t)}$

now notice that we can find $cos(t) = \sqrt[3]{y}$ from the expression for y,

and $sin(t) = \sqrt[3]{x}$ from its expression for x.

Therefore dy/dx can be written in terms of x and y as:

$\frac{dy}{dx} =-\frac{cos(t)}{sin(t)}=-\sqrt[3]{\frac{y}{x} }$

4 0

3 years ago