You change the equation into a y=mx+b form so it would be y=x-6 and so when you graph it, go down six on the y-axis and make a straight line that goes diagonally through the boxes. Not sure if you were asking how to change the equation to graphing form or how to actually graph the line but hopefully this helps. :)
For the answer to the question on w<span>hat is the equation of the quadratic graph with a focus of (5, 6) and a directrix of y = 2?
</span>the vertex = (5,4)
<span>p = 2 </span>
<span>4*2(y-4) = (x-5)^2 </span>
<span>y = (1/8)(x-5)^2 + 4
</span>
I hope my answer helped. Have a nice day!
Answer:
x=7
Step-by-step explanation:
The given equation is:
Multiplying both sides by LCM of 3 and 6
So,
Hence, the solution of the equation is x=7 ..
Check the picture below, that enclosed area is pretty much our "washer".
now, to get the outer radius, or "farther" radius from the axis of rotation, what I usually do is, use the f(x) - g(x) to get the area under the curve, using the axis of rotation for g(x).
Answer:9
Step-by-step explanation: