The midpoint (W) of XY is also on segment PQ, so PQ is the bisector of XY.
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Answer:
The answer in the procedure
Step-by-step explanation:
we have
2x-3y=-1 ----> equation A
3x+3y=26 --> equation B
Solve the system by elimination
Adds equation A and equation B
2x-3y=-1
3x+3y=26
----------------
2x+3x=-1+26
5x=25
x=25/5
x=5
Find the value of y
substitute the value of x in equation A or equation B and solve for y
2(5)-3y=-1
10-3y=-1
3y=10+1
y=11/3
Deficient
ff f f f f f f f f f f f f f ff f f ff f f f f f
Answer: y=4x-7
Step-by-step explanation:
Answer:
n= 11 & n = 13 is the answer
