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KonstantinChe [14]
3 years ago
14

The process of redefining the functionality of a built-in operator, such as , -, and *, to operate on programmer-defined objects

is called operator _____. a. overriding b. overloading c. initializing d. testing
Computers and Technology
1 answer:
Ksenya-84 [330]3 years ago
3 0

It should be noted that the process of redefining the functionality of a built-in operator to operate is known as <u>operator overloading</u>.

Operator overloading simply means polymorphism. It's a manner in which the operating system allows the same operator name to be used for different operations.

Operator overloading allows the operator symbols to be bound to more than one implementation. It's vital in redefining the functionality of a built-in operator to operate on programmer-defined objects.

Read related link on:

brainly.com/question/25487186

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maria [59]

Answer:

<em>Locality of reference.</em>

Explanation:

In computing, The principle of locality of reference is the probability of a processor to repeatedly access the same set of memory locations within a small time interval. This reference of locality can be spatially based (repetitive usage of data within the same location on the computer memory), or temporally based (repetitive usage of a particular data or resources within a shot time interval). The ability of some computing system to perform this action increases their predictability, and efficiency of memory hierarchy use, among other abilities.

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In a batch operating system, three jobs are submitted for execution. Each job involves an I/O activity, CPU time and another I/O
Ilia_Sergeevich [38]

Answer:

a) CPU utilization for uniprogramming system = 18.2%

b) CPU utilization for multiprogramming system = 41.379%

Explanation:

IO time = total time – CPU time

For JOB 1  

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total time= 23ms

IO time = 23-3 = 20ms ,

For JOB 2

CPU time =5ms

total = 29ms

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For JOB 3  

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total = 14ms

IO time = 14-10 =10ms  

1.) In uniprogramming system, operations are performed sequentially

CPU utilization=total CPU time / total real time

CPU utilization =(3+5+4) / (23+29+14)

CPU utilization =0.182 or 18.2%

2) In multiprogramming system, jobs wait for the CPU to get free while performing IO operations concurrently

steps followed by the os

1. IO for 1st job                           at 0ms

2. IO for 2nd job                          at 0ms

3. IO for 3rd job                          at 0ms

4. CPU time for 3rd job              at 5ms

5. Next IO job for 3rd job           at 9ms END at 14ms

6. CPU time for 1st job              at 9ms

7. Next IO job for 1st job           at 14ms END at 23ms

8. CPU time for 2nd job             at 14ms

9. Next IO job for 2nd job          at 15ms END at 29ms

CPU time is 3+5+4 =12ms

Total execution time = 29ms

CPU utilization = 12*100/29= 41.379%

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Answer:

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Answer:

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