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Ghella [55]
2 years ago
8

Find the discriminant of the quadratic equation. 2i2+6i=4

Mathematics
2 answers:
Kitty [74]2 years ago
7 0
<h3 /><h3>{2i}^{2}  + 6i = 4 \\  {8i }^{2}  = 4 \\ 8i =  \sqrt[2]{4}  \\ 8i = 2 \\ i =  \frac{2}{8}  \\ i =  \frac{1}{4}</h3>

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

denpristay [2]2 years ago
5 0

Answer: No solution

Would appreciate brainly <3

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James and Amy play 3 more games.They have played the same number of games as last week .Fill in the blanks to make the equation
Fiesta28 [93]

Question is Incomplete; Complete question is given below;

James and Amy played 12 games of checkers last week. This week they played 7 games on Monday and 2 games on Wednesday.James and Amy play 3 more games. They have played the same number of games as last week. Fill in the blanks to make the equation true. Use +,-, or =. 12_7_2_3 Explain how you chose the symbols.

Answer:

12<u> = </u>7<u> + </u>2<u> + </u>3

Step-by-step explanation:

Given:

Number of games played last week = 12

Number of games played on Monday this week = 7

Number of games played on Wednesday this week = 2

Also given:

James and Amy play 3 more games.

So Number of games played more = 3

We need to fill in the blanks 12 __ 7__2__3 with signs '+', '-','='.

Solution:

It is given that they have played the same number of games as last week.

So we can say that;

Number of games played last week is equal to Number of games played on Monday this week plus Number of games played on Wednesday this week plus Number of games played more.

framing in equation form we get;

12 = 7 + 2+3

Hence we have fill the blanks as 12<u> = </u>7<u> + </u>2<u> + </u>3.

8 0
3 years ago
Find the slope of the line passing through the points (-1,3) and (4,-7)
Step2247 [10]
Slope = (3-(-7))/(-1-4)
= 10/(-5)
= -2
The slope is -2.
3 0
3 years ago
2. A marketing firm is trying to estimate the proportion of potential car buyers that would consider
Maurinko [17]

Answer:

a. The number of people that should be in the pilot study are 600 people

b. The point estimate is 0.62\overline 6

c. At 95% confidence level the true population proportion of potential car buyers of hybrid vehicle is between the confidence interval (0.588, 0.6654)

d. Two ways to reduce the margin of error are;

1) Reduce the confidence interval

2) Use a larger sample size

Step-by-step explanation:

a. The given parameters for the estimation of sample size is given as follows;

The margin of error for the confidence interval, E = 4% = 0.04

The confidence level = 95%

The sample size formula for a proportion as obtained from an online source is given as follows;

n = \dfrac{Z^2 \times P \times (1 - P)}{E^2}

Where, P is the estimated proportions of the desired statistic, therefore, we have for a new study, P = 0.5;

Z = The level of confidence at 95% = 1.96

n + The sample size

Therefore, we have;

n = \dfrac{1.96^2 \times 0.5 \times (1 - 0.5)}{0.04^2} = 600.25

Therefore, the number of people that should be in the pilot study in order to meet this goal at 95% confidence level is n = 600 people

b. The point estimate for the population proportion is the sample proportion  given as follows;

\hat p = \dfrac{x}{n}

Where;

x = The number of the statistic in the sample

n = The sample size

From the question, we have;

The number of potential car buyers, n = 600

The number of respondent in the sample that indicated that they would consider purchasing a hybrid, x = 376

Therefore, the point estimate, for the proportion of potential car buyers that would consider buying a hybrid vehicle, \hat p = 376/600 = 0.62\overline 6

c. The confidence interval for a proportion is given as follows

CI=\hat{p}\pm z\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

Therefore, we get;

CI=0.62 \overline 6\pm 1.96\times \sqrt{\dfrac{\hat{0.62 \overline 6}\cdot (1-\hat{0.62 \overline 6})}{600}}

C.I. ≈ 0.6267 ± 0.0387

The 95% confidence interval for the true population proportion of potential buyers of hybrid vehicle, C.I. =  (0.588, 0.6654)

d. The margin of error is given by the following formula;

MOE_\gamma = z_\gamma  \times \sqrt{\dfrac{\sigma ^2}{n} }

Where;

MOE_\gamma = Margin of error at a given level of confidence

z_\gamma = z-score

σ = The standard deviation

n = The sample size

Therefore, the margin error can be reduced by the following two ways;

1) Reducing the confidence interval and therefore, the z-score

2) Increasing the sample size

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2 years ago
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sineoko [7]
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