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3 years ago

Clara has a positive acceleration for 5 minutes

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

3 0

Answer:

true

Step-by-step explanation:

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2. To which set or sets does the number -14

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It is d im pretty sure

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3 years ago

Simplify each of the the following expression

Papessa [141]

Answer:

International resources means the resources which belong to all the countries of the world. Example: seas and oceans etc. International Resources are regulated by some International institutions. For instance, every country is given some rights over the oceans to a specific range.

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3 years ago

Translate the phrase into an algebraic expression.<br> The product of 9 and y

Alenkinab [10]

Answer:9*y or 9y

Step-by-step explanation:

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3 years ago

Assume that college students have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15. Fin

jolli1 [7]

Answer:

0.018 is the probability that a randomly selected college student has an IQ greater than 131.5

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.

Formula:

a) P(IQ greater than 131.5)

P(x > 131.5)

Calculation the value from standard normal z table, we have,

0.018 is the probability that a randomly selected adult has an IQ greater than 131.5

3 0

3 years ago

I need help in partial fraction!! With simple explaination would be nice!

WITCHER [35]

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}$

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}$

Now the second term can be decomposed into partial fractions.

$\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}$
$\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}$
$4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)$
$4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1$
$\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3$
$\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}$

So

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}$

3 0

3 years ago