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tiny-mole [99]
3 years ago
11

What is the solution to the system of equations plz help everything is in the pic

Mathematics
1 answer:
Aleks [24]3 years ago
8 0

Answer:

Your answer is B. (-2,1)



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"The last time I bought this product, it cost $20.00 but it looks like it costs $29.60 today. Why such a large increase?"
Oksanka [162]

Answer:

The company decided to increase the price by $9.60, or by 48%.

Step-by-step explanation:

To measure the price difference in dollars is simple, just subtract the old price from the new one:

29.60 - 20 = 9.60

Divide the price change by the old price to find the price increase in percentage:

9.60 \div 20 = 0.48 \\ 0.48 \times 100\% = 48\%

5 0
3 years ago
(-5, 4); slope-3<br> So what is the answer
inna [77]
Make a graph and start at the origin (0,0) count down 5 units and across to the right 4 units. Put a dot here. For every 1 unit the line moves to the right, it moves down 3.
4 0
4 years ago
PLEASE PLEASE PLEASE PLEASE SHOW YOUR WORK
stellarik [79]

Answer:

9.11x10^-28

Step-by-step explanation:

1.67x10^-24 would be .000000000000000000000000167 and 9.11x10^-28 would be .0000000000000000000000000000911 and because it has more zeros in front of it, 9.11x10^-28 would be the smaller mass

I'm 99.99999999999999999% sure this is correct.

6 0
3 years ago
Help me with question plz
rewona [7]

Answer:

41

Step-by-step explanation:

What I did was I took 180, 85 and 54 and subtracted them to get 41 if it is wrong i am so very sorry

7 0
3 years ago
Read 2 more answers
Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

5 0
3 years ago
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