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Kobotan [32]
3 years ago
5

Calculator

Mathematics
1 answer:
mixas84 [53]3 years ago
5 0

\text{Given : Which ordered pair is the solution to the system of equations?} \\  \\  \begin{cases}-5x - 3y = 12 \\   y - x = 12 \end{cases}

\text{Solution : According to the question, here let's take these variables as two}  \\  \text{equations then get their value and finally get the answer.} \\  \\  \sf  {1}^{st} \: equation  :  \\ \leadsto \frak{-5x - 3y = 12} \\  \\ \leadsto \frak{-5x = 12 + 3y} \\  \\ \leadsto \frak{x=  \frac{12 + 3y}{-5}} \qquad  \sf ...eq(1) \\  \\  \sf 2^{nd}  \: equation :  \\  \leadsto \frak{y = x - 12} \qquad \sf ...eq(2) \\  \\  \underline{  \frak{finding \: x  }} :  \\  \\  \dashrightarrow \frak{x=  \frac{12 + 3y}{-5}}  \\  \\ \dashrightarrow \frak{x=  \frac{12 + 3(x - 12)}{-5}}  \\  \\  \dashrightarrow \frak{x=  \frac{12 + 3x - 36}{-5}}  \\  \\  \dashrightarrow \frak{-5x=  12 + 3x - 36}  \\  \\  \dashrightarrow \frak{-5x - 3x=   - 24}  \\  \\  \dashrightarrow \frak{-8x =  - 24}  \\  \\  \star \quad \underline{ \boxed{ \green{ \frak{x =  3}}}} \\  \\ \underline{ \frak{ getting \: y}} : \\  \\  \dashrightarrow \frak{y = 3 - 12} \\  \\ \star  \quad\underline{  \boxed{\blue{ \frak{y =  - 9}}}} \\  \\

\green{ \mathbb{HENCEFORTH, \:  THE \:  PAIR \:  IS \:   \pink{\frak{ (3,-9)}}}}

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