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2 years ago

The area of a triangular flower bed in the park has an area of

Mathematics

1 answer:

blagie [28]2 years ago

8 0

Answer:

b = 24 ft

h = 10 ft

Step-by-step explanation:

120 = ½hb

120 = ½h(3h - 6)

240 = h(3h - 6)

240 = 3h² - 6h

80 = h² - 2h

0 = h² - 2h - 80

0 = (h - 10)(h + 8)

h = 10 ft or -8 ft

we ignore -8 as it makes no sense for a triangle side length.

b = 3(10) - 6 = 24 ft

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Mary wants to fill in a cylinder vase. At the flower store they told her that the vase should be filled 3/4 for the flowers to

Alex Ar [27]

Answer:

About 376.99 cubic inches

Step-by-step explanation:

Cylinder has a volume of:

$V=\pi r^2h$

Where

V is the volume

r is the radius

h is the height

We need to find the volume of the cylinder, then multiply that answer by 3/4 to get the solution to this problem. First, the full volume of the cylinder.

Given

r = 4

h = 10

So,

$V=\pi r^2h\\V=\pi (4)^2 (10)\\V=502.65$

Now, we multiply by 3/4:

$502.65*\frac{3}{4}=376.99$

Mary should be vase to 376.99 cubic inches

4 0

3 years ago

Jenny can type at a speed of 80 words per minute. It took her 20 minutes to type a report. How many words was the report?

horsena [70]

80words=1min so you would multiply 80 by 20 which is 1,600 words for 20 minutes

7 0

3 years ago

Read 2 more answers

AB and DE are chords that intersect at point F inside circle C as shown. If the measure of arc EA= 50 degrees and the measure of

defon

Answer:

Part 1) $m\angle AFE=55^o$

Part 2) $m\angle EFB=125^o$

Step-by-step explanation:

Part 1) what is the measure of angle AFE

we know that

The measure of the interior angle is the semisum of the arches that comprise it and its opposite.

<u>Note:</u> In this problem the correct measure of arc EA is 40 degrees (see the picture)

$m\angle AFE=\frac{1}{2}(arc\ EA+arc\ DB)$

substitute the given values

$m\angle AFE=\frac{1}{2}(40^o+70^o)=55^o$

Part 2) what is the measure of angle EFB?

we know that

$m\angle AFE+m\angle EFB=180^o$ ---> by supplementary angles (form a linear pair)

substitute the given value

$55^o+m\angle EFB=180^o$

$m\angle EFB=180^o-55^o=125^o$

8 0

3 years ago

What is the common factors of 12 and 42 also 63 and 84

kaheart [24]

$12|2 \\ 6 \ |2 \\ 3 \ |3 \\ 1 \\\\12=2^2*3 \\\\ 42|2\\21|3\\7\ |7\\1 \\\\42=2*3*7 \\\\ G.C.F(12;42)=2*3=6 \\\\\\\ 63|3 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 63=3^2*7 \\\\ 84|2 \\ 42|2 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 84=2^2*3*7 \\\\ G.C.F(63;84)=3*7=21$

3 0

3 years ago

What is the answer to this problem

Sveta_85 [38]

Answer:

blah

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers