2 years ago

The mean of 17,x,10,17,51 is 21 find x

Mathematics

1 answer:

KIM [24]2 years ago

8 0

Answer:

x=10

Step-by-step explanation:

(17+x+10+51+17)/5=21

95+x=105

x=10

You might be interested in

Six copies of a book cost $90. How much does<br> each copy of the book cost?

IRINA_888 [86]

Each book costs $15. 90 divided by 6 is 15 which is also 90 over 6.

6 0

2 years ago

Read 2 more answers

Elda has a rectangular piece of paper with an area of 0.12m squared. She cuts this piece of paper into small rectangles each wit

Lisa [10]

The maximum number is 6.

7 0

3 years ago

Which of the following are statistical questions? Select all that apply.

Olegator [25]

The answers are a b c d e or all of them except the chocolate chip one

5 0

2 years ago

I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5

Gnesinka [82]

Given:
$f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}$

Using
$\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}$
we derive
$\frac{d}{dx}4xcos^{-1}(2x+4)$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}$

Similarly, using
$\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}$
we derive
$\frac{d}{dx}(-\sqrt{3-3x^2})$
$=\frac{3x}{\sqrt{3-3x^2}}$

Therefore, the derivative is
$f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}$

3 0

3 years ago

Read 2 more answers

M∠A = 40º

denis23 [38]

180-40=140. 140/5 = 28

x= 28

angle B: 5(28) = 140
140 + 40 = 180

180=180

7 0

3 years ago