Does anyone have the answer and the grading table for this test? Its name is 05 2019 Int. I have searched high and low but can't
find it. No links, please help me!
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Please do not spam this question if you don't know the answer, or I will report you. Thank you!
1 answer:
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Based on the calculations, we have the following:
- The area of the sheet of paper is 96 square inches.
- The combined area of the triangle cutouts is equal to 36 square inches.
- The area of the parallelogram is equal to 60 square inches.
- The altitude of the parallelogram is equal to 6.51 square inches.
<u>Given the following data:</u>
- Dimension of paper = 12-inch by 8-inch.
Mathematically, the area of the paper is given by this formula:
Area = 96 square inches.
<u>For the four (4) right triangles:</u>
- Dimension 1 = 2 inches by 9 inches.
- Dimension 2 = 3 inches by 6 inches.
Therefore, the combined area of the triangle cutouts is given by:
This would be determined by subtracting the area of the four (4) right triangles from the areas of the paper as follows:
P = 60 square inches.
<h3>The altitude of the parallelogram.</h3>Altitude = 6.51 square inches.
Read more on parallelogram here: brainly.com/question/4459854
<u>Complete Question:</u>
A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimensions 2 inches by 9 inches, and the other two have the dimensions 3 inches by 6 inches. The resulting parallelogram has a base of approximately 9.22 inches.