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exis [7]
3 years ago
14

random sample has been taken from a normal population and two confidence intervals constructed using exactly the same data. The

two CIs are (38.02, 61.98) and (39.95, 60.05). (a) What is the value of the sample mean
Mathematics
1 answer:
Zepler [3.9K]3 years ago
5 0

The sample mean of the random sample is 50

The margin of error (E) is the amount of error allowed in the random sample.

The confidence interval (CI) is given by:

CI = μ ± E = (μ - E, μ + E)

Given a confidence interval of (38.02, 61.98), hence:

μ - E = 38.02     (1)

μ + E = 61.98     (2)

Hence solving equations 1 and 2 simultaneously gives:

μ = 50, E = 11.98

Hence the sample mean of the random sample is 50

Find out more at: brainly.com/question/24131141

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8 0
4 years ago
4 years ago a pint of milk
fenix001 [56]

Given-

Cost of milk 4 years ago = £1.05

To find-

Percentage increase in cost

Solution-

Increase in cost = £ ( 1.26 - 1.05 )

→ £ 0.21

Percentage increase :-

\frac{0.21}{1.05} \times 100

→ 20

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5 0
3 years ago
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uranmaximum [27]

i think its 12

Step-by-step explanation:

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3 years ago
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gladu [14]

Answer:

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4 0
4 years ago
A magazine provided results from a poll of 2000 adults who were asked to identify their favorite pie. Among the 2000 ​respondent
ladessa [460]

Answer:

95%

Step-by-step explanation:

For a given sample data, the width of the confidence interval would vary directly with the confidence level i.e. more the confidence level,  wider will be the confidence interval.

This is because the critical value associated with the confidence level(e.g z value) becomes larger as the confidence level is increased which results in an increased interval.

The confidence interval for a population proportion is given by the formula:

p \pm z\sqrt{\frac{pq}{n} }

So, for a fixed value of p,q and n, the larger the value of z the wider will be the confidence interval.

Hence 95% confidence interval will be wider than 80% confidence interval.

7 0
4 years ago
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