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2 years ago

a five-card hand is dealt at random from a standard deck. What is the probability that the hand contains exactly two black cards

1 answer:

6 0

Using the principle of binomial probability, the probability of having exactly two black cards is 0.3125

Probability of having a black card = 26/52 = 1/2

Using the binomial probability relation :

P(x = x) = nCx * p^x * q^(n-x)
p = probability of success = 1/2 = 0.5
Number of picks, n = 5
q = 1 - p = 0.5
x = 2

Hence,

P(x = 2) = 5C2 × 0.5² × 0.5³

P(x = 2) = 10 × 0.25 × 0.125

P(x = 2) = 0.3125

Hence. Probability of having exactly 2 black cards is 0.3125

Learn more : brainly.com/question/12474772

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9(3+c+4) what is the answer

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Answer:

the answer is 9c+63

Step-by-step explanation:

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3 years ago

Which ordered pair is in the solution set y-5>-3x (4,-2) (1,2) (-1,-3) (-2,4)

Lisa [10]

The ordered pair that satisfies the given inequality is ( 4,-2)

Step-by-step explanation:

By looking at the Graph, only the point ( 4,-2) marked by red dot lies on the shaded portion of the graph.

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3 years ago

Let f be defined as shown. What is f^-1(1)?

FinnZ [79.3K]

Answer:

From the above image when the input of f(x) is 9 the output is 1

So f^-1(1) is just the reverse when the input is 1 the output is 9

So f^-1(1) = 9

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3 years ago

at 111111:55\text{ p.m.}55 p.m.55, start text, space, p, point, m, point, end text, thomas ties a weight to the minute hand of a

Ahat [919]

The trigonometric function's formula, which simulates the torque (tau) that the weight applied t minutes after Thomas attached it is

$3 Sin (\frac{2\frac{22}{7} }{60} (t-51))$

The angular speed of the minutes hand is

$w = \frac{2 (\frac{22}{7}) }{60}$ rad/min

Following the application of weight, the torque as a function of time t is,

$t= t_{0} sin (w (t-5) min)\\ = (3 Nm) sin ((\frac{2 (\frac{22}{7} }{60} ) rad/min (t-5) min)$

$= (3 Nm) sin ( \frac{2 (\frac{22}{7} }{60} (t-5) rad ) \\= 3 sin (\frac{2 \frac{22}{7} }{60} (t-5)$

<h3>What is torque ?</h3>

Torque, which is also known as the moment of a force, is the propensity of a force to rotate the body to which it is applied. Force (F) x Distance (r) = Torque is how torque is calculated. The distance (r) between the pivot point and the force's action point. A vector quantity is a torque. As a vector quantity, torque always has a direction that is perpendicular to the plane that contains the vectors of force and displacement.

To learn more about Torque, visit

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2 years ago

After all your hard work studying for Algorithms you, Alice and Bob end up stuck in a room full of deadly zombies! Luckily you h

shutvik [7]

Answer:

The most important quantity to consider in order to answer this question is the arrival time of the zombies from their initial position, which is the quotient between their distance to the visitors, divided the zombie's speed.

See explanation below.

Step-by-step explanation:

Part 1)

What is crucial to know is what is the time at which each zombie would reach Alice and Bob, and that is given by the quotient between the distance away each zombie is, divided by the zombie's speed:

$speed=\frac{distance}{time} \\time=\frac{distance}{seed} \\t_i=\frac{d_i}{s_i}$

Then, it is this quotient for each zombie, that one has to estimate given the input values distance and speed, and it is the output "time" ( $t_i$ ) for each zombie, what we need to analyze so as to prioritize an order regarding which zombie to kill first.

Part 2)

Shooting the closest zombie first is not a good idea, since the speed of that closest zombie may be much slower than another zombie further away, but with much larger speed. Again, the important value to analyze is the time that it would take each zombie to reach Alice and Bob.

Part 3)

Shooting the fastest zombie first is not a good idea either, because that fastest zombie could be located very far away from the visitors, and other zombies closer by may reach them first.

Part 4)

The order that should be used to kill the zombies is given by the value of the time to reach Bob and Alice based on the quotient distance (di) over speed (si) explained in Part 1). The zombie that shows smallest time should be shot first, and then the others in increasing order of time value.

Part 5)

Notice that the individual zombie information is not presented in the question, but the student should be able to calculate the quotients for each zombie, and considering that there could be at most one shot every second, estimate the number of seconds that the time for each zombie in increasing order would allow until the addition of shooting time per second in the appropriate order cannot match the arrival time of the zombies that are left.

One should count number of seconds from the first shot (to the zombie with shortest arrival time), and then increase in one unit (one shot per second), to the following zombie with slightly larger arrival time), and so on, until the addition of seconds (one second per shot and per increasing arrival time of zombie) exceeds the next zombie arrival time.

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3 years ago