(1/A) dA/dt= C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
The one on the left is b and the one on the right is -1.
Answer:
C 30%
Step-by-step explanation:
87.50/125= 0.70
1-0.7-0.3
Answer:
60km
Step-by-step explanation:
we multiply 30 with 2 and we get the answer as 60km in two hours.
First answer: Graph A
Second answer: E) Increase less
Graph A shows a flatter curve compared to B which is steeper. The steeper the curve, the faster the increase.
