I believe the answer is all of the above
The expression to find the sum of terms of the series is; Sₙ = 3(1 - ¹/₂ⁿ)
<h3>How to solve Geometric series?</h3>
We are given the series;
3/2 + 3/4 + 3/8 + 3/16 +.....
Formula for the nth term of a geometric series is;
aₙ = ar^(n - 1)
where;
a is first term
r is common ratio
From our given series;
a = ³/₂
r = (³/₄)/(³/₂) = ¹/₂
We know that Sum of GP when n < 1 is;
Sₙ = a(1 - rⁿ)/(1 - r)
Thus;
Sₙ = ³/₂(1 - ¹/₂ⁿ)/(1 - ¹/₂)
Sₙ = 3(1 - ¹/₂ⁿ)
Thus, the expression to find the sum of terms of the series is; Sₙ = 3(1 - ¹/₂ⁿ)
Read more about Geometric Series at; brainly.com/question/24643676
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Answer:
The answer is 0.9599.
Explanation:
mu (sample) = mu = 8.4
s.d. (sample) = 1.8/ sq. rt. 40
P( greater than 8.1) = (8.9-8.4)/(1.8/ sq. rt. 40)
Let x be the mean time for the 40 mechanics
Standardize the mechanics: (8.9-8.4)/(1.8/ sq. rt. 40) = 1.75 = Z
P( x > 8.9) = P(Z > 1.75), this means the area to the right of Z = 1.75.
Then you need to look in the table of the Normal distribution, Z(1.75) =0.9599
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<em>*laughs in morse code*</em>
