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melisa1 [442]
3 years ago
11

A strawberry that you left overnight at school started to grow mold. There

Mathematics
1 answer:
blondinia [14]3 years ago
4 0

Answer: The molds density of the mold is 11:11

Step-by-step explanation:

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2. Find the value of x.
My name is Ann [436]

Answer:

x = 6

Step-by-step explanation:

3(x + 2) =24

Divide each side by 3

3/3(x+2) = 24/3

x+2 = 8

Subtract 2 from each side

x+2-2 = 8-2

x = 6

4 0
3 years ago
Read 2 more answers
Find the value in 3 of <br> 6035 ?
Katena32 [7]
The 3 is in the tens place.

3*10=30

Final answer: The value of the 3 is 30 since it is in the tens place.
6 0
3 years ago
Are the ratios 20:9 and 2:1 equivalent?<br> yes or no
marusya05 [52]

Answer:

No

Step-by-step explanation:

Do they have common factors?

No which is why they are not able to be simplified further

so no

5 0
2 years ago
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If MP is a perpendicular bisector to LN, find each value (picture attached)
solong [7]

Answer:

x=4, MN= 37, LM= 37, y=7.

Step-by-step explanation:

If MP is a perpendicular bisector to LN, then NP and LP are equivalent.

(Solve for y)

2y+2= 16

(Move the +2 to the right side of the equation)

2y= 14

(Divide both sides by 2 to isolate the variable)

y=7

To find x and the measure of MN and LM, solve for x in the following equation:

7x+9 = 11x-7

(Move 7x to the right side of the equation)

9 = 4x-7

(Move -7 to the right side of the equation.)

16= 4x

(Divide both sides by 4 to isolate the variable.)

4= x

Plug x back into both equations to get the measure of MN and ML

MN=7(4)+9

MN= 28+9

MN= 37

LM= 11(4)-7

LM= 44-7

LM= 37

I hope this helps!

3 0
3 years ago
Read 2 more answers
Evaluate the expression using the values in the left column to complete the table
egoroff_w [7]

Answer/Step-by-step explanation:

A. 4b + 3b

Using b = 2

4(2) + 3(2) = 8 + 6 = 14

Using b = 4

4(4) + 3(4) = 16 + 12 = 28

Using b = 6

4(6) + 3(6) = 24 + 18 = 42

Using b = 8

4(8) + 3(8) = 32 + 24 = 56

Using b = 10

4(10) + 3(10) = 40 + 30 = 70

Using b = 2

4(12) + 3(12) = 48 + 36 = 84

B. 3(x - 2)

Using x = 3

3(3 - 2) = 3(1) = 3

Using x = 5

3(5 - 2) = 3(3) = 9

Using x = 7

3(7 - 2) = 3(5) = 15

Using x = 9

3(9 - 2) = 3(7) = 21

Using x = 11

3(11 - 2) = 3(9) = 27

Using x = 13

3(13 - 2) = 3(11) = 33

C. 5(4a - 1)

Using a = 2

5(4(2) - 1) = 5(8 - 1) = 5(7) = 35

Using a = 3

5(4(3) - 1) = 5(12 - 1) = 5(11) = 55

Using a = 4

5(4(4) - 1) = 5(16 - 1) = 5(15) = 75

Using a = 5

5(4(5) - 1) = 5(20 - 1) = 5(19) = 95

Using a = 6

5(4(6) - 1) = 5(24 - 1) = 5(23) = 115

Using a = 7

5(4(7) - 1) = 5(28 - 1) = 5(27) = 135

D. 6y - 2y + 4

Using y = 2

6(2) - 2(2) + 4 = 12 - 4 + 4 = 12

Using y = 3

6(3) - 2(3) + 4 = 18 - 6 + 4 = 18 - 2 = 16

Using y = 5

6(5) - 2(5) + 4 = 30 - 10 + 4 = 30 - 6 = 24

Using y = 10

6(10) - 2(10) + 4 = 60 - 20 + 4 = 60 - 16 = 44

Using y = 8

6(8) - 2(8) + 4 = 48 - 16 + 4 = 48 - 12 = 36

Using y = 6

6(6) - 2(6) + 4 = 36 - 12 + 4 = 36 - 8 = 28

7 0
3 years ago
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