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Kryger [21]
3 years ago
11

Rewrite d= 2r in function notation

Mathematics
1 answer:
Delvig [45]3 years ago
3 0
R = d over 2 or r = d / 2 hope this helps 
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Can you guys please help me? I understand everything but the last step.​
MariettaO [177]

Answer:

It is because you have to get rid of the power of 2 from c. In order to get rid, you have to square root it on both sides :

c² = 74

√(c²) = √74

c^(1/2×2) = √74

c = √74

Using Indices formula, (a^m)^n = a^(mn)

8 0
4 years ago
Which set of points lies on the the graph of the function.
meriva

Answer:

(0,0), (-1, 1), and (1,-1)

Step-by-step explanation:

If you were to plot all the points they would all end up being on the green line

I hope this helped?

8 0
3 years ago
Read 2 more answers
What is 32\68 in simpilest form
Paha777 [63]
32/68 can be reduced to 8/17.
5 0
3 years ago
Read 2 more answers
Help me with this question I don't get it
Shtirlitz [24]
Carolyn has more than enough paint to cover that wall because she has a gallon of paint that can be done to get the wall painted.
7 0
3 years ago
The parent function, f(x)=5^x has been vertically compressed by a factor of one-half shifted to the right three units and down t
Artist 52 [7]

Answer:

The required function is g(x)=\frac{1}{2}(5^{x-3})-2.

Step-by-step explanation:

The given parent function is

f(x)=5^x

The transformation of a parent function is defined as

g(x)=kf(x+a)+b

Where, k represents the vertical stretch or compression, a represents the horizontal shift and b represent the vertical shift.

→ If |k|>1, then it represents vertically stretch and If |k|<1, then it represent vertically compression.

→ If a>0, then f(x) shifts left by a units and If a<0, then f(x) shifts right by a units.

→If b>0, then f(x) shifts upward by b units and If b<0, then f(x) shifts downward by b units.

Since the graph of f(x) has been vertically compressed by a factor of one-half shifted to the right three units and down two units.

k=\frac{1}{2}

a=-3

b=-2

The graph of required function is

g(x)=\frac{1}{2}f(x-3)-2

g(x)=\frac{1}{2}(5^{x-3})-2

Therefore the required function is g(x)=\frac{1}{2}(5^{x-3})-2.

8 0
4 years ago
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