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2 years ago

How many possibilities with 6 numbers and one letter.

Mathematics

1 answer:

WITCHER [35]2 years ago

8 0

Answer:

127

Step-by-step explanation:

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Choose the correct simplification of x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4t

Umnica [9.8K]

Answer:

<h3>The option A) $x^{10}z^7$ is correct answer.</h3><h3>The correct simplification for the given expression $\frac{x^{12}\times z^{11}}{x^2\times z^4}$ is $x^{10}z^7$ </h3>

Step-by-step explanation:

Given expression is x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power.

The given expression can be written as $\frac{x^{12}\times z^{11}}{x^2\times z^4}$

<h3>To choose the correct simplification of the given expression :</h3>

Now we have to simplify the given expression as below

$\frac{x^{12}\times z^{11}}{x^2\times z^4}$

$=x^{12}\times z^{11}(x^{-2}\times z^{-4})$ ( by using the identity $\frac{1}{a^m}=a^{-m}$ )

$=(x^{12}.x^{-2})\times (z^{11}.z^{-4})$

$=x^{12-2}\times z^{11-4}$ ( by using the identity $a^m.a^n=a^{m+n}$ )

$=x^{10}\times z^7$

$=x^{10}z^7$

∴ $\frac{x^{12}\times z^{11}}{x^2\times z^4}=x^{10}z^7$

<h3>The correct simplification for the given expression $\frac{x^{12}\times z^{11}}{x^2\times z^4}$ is $x^{10}z^7$ </h3><h3>Hence option A) $x^{10}z^7$ is correct answer.</h3>

4 0

3 years ago

I neeeeed help thankyou

Helen [10]

Answer:

what one

Step-by-step explanation:

if it is the left one it is -7(2x)+-7(7)+10x=-4x

7 0

3 years ago

PLEASE HELPPPPP!!!!!!!!! (show work if you can)

Kryger [21]

Answer:

$180x^4y^3z^2$

Step-by-step explanation:

Start by finding the LCM of the coefficients of each polynomial:

$LCM(12,18,30)=180$

Next, to find the least common multiple of each of the following terms, we need to take the absolute minimum we can of each term ( $x$ , $y$ , and $z$ ). The largest term of $x$ is $x^4$ in the first polynomial, so we'll take exactly that for our $x$ term in the LCM, absolutely nothing more. Similarly, the largest term of $y$ in any of the three polynomials is $y^3$ (also in the first polynomial) and the largest $z$ term in any of the three polynomials is $z^2$ in the second polynomial. Thus, the LCM of all our polynomials is: