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tigry1 [53]
2 years ago
15

If 8 family members choose to play "Secret Santa," how many different ways can the names be paired?

Mathematics
2 answers:
Irina-Kira [14]2 years ago
8 0

Answer:

the names can be paired 2 members by 4

Step-by-step explanation:

viktelen [127]2 years ago
3 0

Answer:

300,000,000 or three hundred million

Step-by-step explanation:

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2. Find the value of <img src="https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B1728%7D%20%2B%20100%20%5Csqrt%5B4%5D%7B81%7D%20-%20%286
Taya2010 [7]

Answer:

(b) 0

Step-by-step explanation:

Assuming a typo in the last term:

5 (1728)^(1/3) + 100(81)^(1/4) - ( 6(10)^(1/2) )^2

=5(12) + 100(3) -36(10)

=60+300-360

=0

5 0
2 years ago
Read 2 more answers
Find the difference: 7 7/8 - 3 1/4
DIA [1.3K]
In order to subtract mixed fractions, we must convert them into improper fractions first. To do this simply multiply the whole number by the denominator and add the numerator. The product of this operation will be the new numerator (the whole number is no longer present).

(56 + 7)/8 - (12 + 1)/4
= 63/8 - 13/4

Now that we have our fractions in improper form, we must find the least common denominator which is 8. To avoid changing the value of the second fraction, multiply both the numerator and denominator by 2 (which is essentially 2/2 which equals to 1).

63/8 - 26/8
= 37/8
8 0
3 years ago
4.26 as a decimal in simplest form
Bess [88]
You can not put a decimal to a decimal.So you meant to put a decimal to a fraction and the answer would be: 4.26 as decimal fraction = 426/100
6 0
3 years ago
Two companies, A and B, make express delivery for small-item packages in a city. Company A charges a flat fee of RM70 per packag
bazaltina [42]

Using the <u>normal probability distribution and the central limit theorem</u>, it is found that:

a) There is a 0.1922 = 19.22% probability that Company B would charge more than Company A to deliver a small-item package.

b) The mean amount charged is of RM 51.5, with a standard deviation of 21.35.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem:

  • When a <u>fixed constant k</u> multiplies a variable, the mean is k\mu and the standard deviation is k\sigma
  • When two normal variables are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question, b is needed to solve a, so I am going to place the solution to item b first.

Item b:

Flat fee of RM20(not considered for the standard deviation), plus a variable fee of RM3.5, hence:

\mu_B = 20 + 3.5(9) = 51.5

\sigma = 6.1(3.5) = 21.35

The mean amount charged is of RM 51.5, with a standard deviation of 21.35.

Item a:

This probability is P(B - A) > 0. For the distribution, we have that:

\mu_{B-A} = \mu_B - \mu_A = 51.5 - 70 = -18.5

Since A has a constant fee, it's standard deviation is 0, hence:

\sigma_{B-A} = \sqrt{\sigma_A^2 + \sigma_B^2} = \sqrt{21.35^2} = 21.35

The probability is <u>1 subtracted by the p-value of Z when X = 0</u>, so:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 + 18.5}{21.35}

Z = 0.87

Z = 0.87 has a p-value of 0.8078.

1 - 0.8078 = 0.1922.

0.1922 = 19.22% probability that Company B would charge more than Company A to deliver a small-item package.

A similar problem is given at brainly.com/question/25403659

3 0
2 years ago
Solve for u<br><br> -5(-5u+5)-8u=5(u-5)-4
sergij07 [2.7K]

- 5( - 5u + 5) - 8u = 5(u - 5) - 4

25u - 25 - 8u = 5u - 25 - 4

17u - 25 = 5u -29

17u - 5u =  - 29 + 25

12u =  - 4

u =   \frac{ - 4}{12}

u =  -  \frac{1}{3}

3 0
2 years ago
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