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Vinil7 [7]
2 years ago
7

Scores on a recent exam followed a normal distribution and letter grades will be assigned with 15% A, 35% B, 30% C, 15% D, and 5

% F. Suppose that Sue took the exam and had a standardized score of 0.85. What letter grade will Sue get?
Mathematics
1 answer:
noname [10]2 years ago
5 0

Using the normal distribution, it is found that Sue will get a letter grade of B.

In a <em>normal distribution </em>with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem, Sue got a grade of 0.85, hence z = 0.85.

  • Looking at the z-table, z = 0.85 has a p-value of 0.8023, hence she is approximately in the top 20%, which is below the top 15% but above the top 50%, hence she got a letter grade of B.

A similar problem is given at brainly.com/question/25745464

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GCF of given monomials are 4a^2

<em><u>Solution:</u></em>

<em><u>Given that we have to find the greatest common factor</u></em>

Given monomials are:

20a^3 \text{ and } 8a^2

When we find all the factors of two or more numbers, and some factors are the same, then the largest of those common factors is the Greatest Common Factor

Let us first find the GCF of 20 and 8 and then find GCF of variables and then multiply them together

<em><u>GCF of 20 and 8:</u></em>

The factors of 8 are: 1, 2, 4, 8

The factors of 20 are: 1, 2, 4, 5, 10, 20

Then the greatest common factor is 4

GCF\ of\ a^3 \text{ and } a^2\\\\a^3 = a^2 \times a\\\\a^2 = a^2

Thus GCF is a^2

<em><u>Therefore GCF of monomials are:</u></em>

\text{GCF of } 20a^3 \text{ and } 8a^2 = 4 \times a^2 = 4a^2

Thus GCF of given monomials are 4a^2

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