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Vinil7 [7]
2 years ago
7

Scores on a recent exam followed a normal distribution and letter grades will be assigned with 15% A, 35% B, 30% C, 15% D, and 5

% F. Suppose that Sue took the exam and had a standardized score of 0.85. What letter grade will Sue get?
Mathematics
1 answer:
noname [10]2 years ago
5 0

Using the normal distribution, it is found that Sue will get a letter grade of B.

In a <em>normal distribution </em>with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem, Sue got a grade of 0.85, hence z = 0.85.

  • Looking at the z-table, z = 0.85 has a p-value of 0.8023, hence she is approximately in the top 20%, which is below the top 15% but above the top 50%, hence she got a letter grade of B.

A similar problem is given at brainly.com/question/25745464

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Help please! I’ll give brainliest too!
DIA [1.3K]

Answer:

y-intercept: -5

Slope: 4

Equation: y = 4x - 5

Step-by-step explanation:

✔️The y-intercept is the value of y when x = 0. From the table of values, it shows that when x = 0, y = -5. Therefore:

y-intercept (b) = -5

✔️using two pairs from the table, (1, -1) and (2, 3):

Slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 -(-1)}{2 - 1} = \frac{4}{1} = 4

Slope = 4

✔️To write an equation for the function, substitute m = 4, and b = -5 into y = mx + b.

Thus:

y = 4x +(-5)

y = 4x - 5

7 0
3 years ago
What is the equation of the line that passes through the point (-2,2) and (0,5)? A. Y=-3/2x+5 B.Y=x-5 C.Y=3/2x+5 D. Y=x+5
Bond [772]
Bbbbbbbbbbbbbbbbbbbbbbbb
6 0
3 years ago
Solve the equation. Check for extraneous solutions. |x - 4| = 5x + 12<br><br> x = []
kykrilka [37]

The solution of the equation is x = -4/3.

<h3>What does it mean to solve an equation?</h3>

An equation represents equality of two or more mathematical expression.

Solutions to an equation are those values of the variables involved in that equation for which the equation is true.

WE have been given an equation as;

|x - 4| = 5x + 12

In an absolute value equation, we solve the original expression as our first equation. Our second one is that we multiply the right side by -1.

Case 1: original equation

|x - 4| = 5x + 12

x - 4 = 5x + 12

x - 5x = 12 + 4

-4x = 16

x = -4

Case 2: Opposite equation

|x - 4| = 5x + 12

x - 4 = - (5x + 12)

x - 4 = - 5x - 12

x + 5x = -12 + 4

6x = -8

x = -4/3

Now we have two solutions. We need to check for extraneous solutions because of all the manipulations;

Check:

|x - 4| = 5x + 12

use x = -4

|-4 - 4| = 5(-4) + 12

| -8 | = -20 + 12

8 = -8              

Thus, it is Not a solution

Now,  |x - 4| = 5x + 12

use x =  -4/3

| -4/3 - 4| = 5( -4/3) + 12

|-16/3 | = -20/3 + 12

|-16/3 | = 16/3

16/3 = 16/3

Thus, it is the  Solution.

Learn more about solving equations here:

brainly.com/question/18015090

#SPJ1

5 0
2 years ago
You return from a trip with 480 Canadian dollars. How much are your Canadian dollars worth in U.S. dollars? Use the exchange rat
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591 Dollars 42 Cents (591 Dollars when rounded)

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4 / 7 * 2 / 3 * *9/16
lara31 [8.8K]

\bf \cfrac{4}{7}\cdot \cfrac{2}{3}\cdot \cfrac{9}{16}\implies \cfrac{4}{16}\cdot \cfrac{9}{3}\cdot \cfrac{2}{7}\implies \cfrac{1}{4}\cdot \cfrac{3}{1}\cdot \cfrac{2}{7}\implies \cfrac{1}{7}\cdot \cfrac{3}{1}\cdot \cfrac{2}{4}\implies \cfrac{1}{7}\cdot \cfrac{3}{1}\cdot \cfrac{1}{2}\\\\\\\cfrac{1\cdot 3\cdot 1}{7\cdot 1\cdot 2}\implies \cfrac{3}{14}

4 0
3 years ago
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