Answer:
19.9
Step-by-step explanation:
we can write the following equation
18000(1.02)^n
where n is the number of years
so we have
26700=18000(1.02)^n
solve for n
1.483=1.02^n
use logs to solve for n
n=19.9
Given:
Temperature in the morning = 6°F.
By the late afternoon, the temperature had dropped 9°F.
To find:
The temperature by the late afternoon.
Solution:
Temperature by the late afternoon = Morning temperature - Dropped temperature
Using the given values and the above formula, we get
Temperature by the late afternoon = 6°F - 9°F
Temperature by the late afternoon = -3°F
Therefore, the temperature by the late afternoon is -3°F.
The cosine of 30° is √3 / 2.
Since cosine is Adjacent over Hypotenuse, Hypotenuse = (2 / √3) * 9 = 18 / √3.
The cosine of 45° is √2 / 2.
Therefore, X = (2 / √2) * (18 / √3) = 36 / √6 = 18 / √1.5 = C
