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2 years ago

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Doctors are interested in determining if the human body temperature is really 98.6 degrees. he selects 30 students and records t

heir temperature using a digital thermometer. what type of test would they conduct to test this claim?

1 answer:

MaRussiya [10]2 years ago

5 0

Answer:

I think its one mean, if it's not I'm very sorry

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Find the derivative of <img src="https://tex.z-dn.net/?f=tan%5E%7B-1%7D%20x" id="TexFormula1" title="tan^{-1} x" alt="tan^{-1} x

sladkih [1.3K]

$\huge{\color{magenta}{\fbox{\textsf{\textbf{Answer}}}}}$

$\frak {\huge{ \frac{1}{1 + {x}^{2} } }}$

Step-by-step explanation:

$\sf let \: f(x) = { \tan }^{ - 1} x \\ \\ \sf f(x + h) = { \tan}^{ - 1} (x + h)$

$\sf f'(x) = \frac{f(x+h) - f(x) }{h}$

$\sf \implies \lim_{ h \to 0 } \frac{ { \tan }^{ - 1}(x + h) - { \tan}^{ - 1}x }{h} \\ \\ \\ \sf \implies \lim_ {h \to 0} \frac{ { \tan}^{ - 1} \frac{x + h - x}{1 + (x + h)x} }{h}$

By using

$\sf { \tan}^{ - 1} x - { \tan}^{ - 1} y = \\ \sf { \tan}^{ - 1} \frac{x - y}{1 + xy} formula$

$\sf \implies \large \lim_{h \to0 } \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{h} \\ \\ \\ \sf \implies \large{\lim_{h \to0} } \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{ \frac{h}{1 + hx + {x}^{2} } \times (1 + hx + {x}^{2} )} \\ \\ \\ \sf \implies \large \lim_{h \to0} \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{ \frac{h}{1 + hx + {x}^{2} } } + \lim_{h \to0} \frac{1}{1 + hx + {x}^{2} }$

<u>Now</u><u> </u><u>putting</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>h</u><u> </u><u>=</u><u> </u><u>0</u>

<u> $\sf \large \implies 0 + \frac{1}{1 + 0 + {x}^{2} } \\ \\ \\ \purple{ \boxed { \implies \frac{1}{1 + {x}^{2} } }}$ </u>

6 0

2 years ago

A school-bus is dropping students off after school. When the bus left the

Verdich [7]

Answer:

60%

Step-by-step explanation:

40-16=24

24/40=0.6

0.6*100=60

First, work out the difference (decrease) between the two numbers you are comparing.

Decrease = Original Number - New Number

Next, divide the decrease by the original number and multiply the answer by 100.

% Decrease = Decrease ÷ Original Number × 100

3 0

3 years ago

Read 2 more answers

20 pts to whoever helps!!

VladimirAG [237]

<h3>Answer: B) 31.348</h3>

======================================

Work Shown:

We will never use the alpha = 0.05 value when computing the test statistic. So we can ignore alpha for this particular problem.

-------

n = 40 is the sample size.

s = 2.6 is the sample standard deviation

$\sigma$ = sigma = 2.9 is the population standard deviation (ie the claimed standard deviation for all the pay phones)

Test Statistic for chi-square

$\chi^2 = \frac{(n-1)*s^2}{\sigma^2}\\\\\chi^2 = \frac{(40-1)*(2.6)^2}{(2.9)^2}\\\\\chi^2 = \frac{39*6.76}{8.41}\\\\\chi^2 = \frac{263.64}{8.41}\\\\\chi^2 \approx 31.3483947681332\\\\\chi^2 \approx 31.348\\\\$

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2 years ago

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What is -14 divided by -2

Svetradugi [14.3K]

A negative divided by a negative is a positive, so -14/-2 = 7
Hope this helped!

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3 years ago

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Can someone factor this problem for me?

Likurg_2 [28]

Your factored answer will be

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