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likoan [24]
2 years ago
7

1. The equation y = -x2 - 2x + 8 is graphed on the

Mathematics
1 answer:
aalyn [17]2 years ago
7 0

Answer:

It B since The root is obtained when F(x)=0 and if F(x)=y this means y=0 and when you look art graph the y=0 presented in two points x=-4 and x=2

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(7z^3+42z^2-15z+1)- (36z^2+12z-21)​
My name is Ann [436]

Answer:

7z^3+6z^2-27z+22

Step-by-step explanation:

The given question is of subtraction:

So,

(7z^3+42z^2-15z+1)- (36z^2+12z-21)​

=7z^3+42z^2-15z+1-36z^2-12z+21

Combining alike terms to simplify

=​7z^3+42z^2-36z^2-15z-12z+1+21

=7z^3+6z^2-27z+22

So the answer in simplified form is:

7z^3+6z^2-27z+22 ..

6 0
3 years ago
Read 2 more answers
Can someone explain what these types of arrows mean please?
Yakvenalex [24]
I think it means grater or less ? Or positive or negative?
8 0
3 years ago
A coordinate grid is shown below: A coordinate grid from negative 2 to 0 to positive 2 is drawn. There are three grid lines betw
Anastasy [175]

Answer:

Part A: 0

Part B: (-1,-1) since point (-1,1) is located in quadrent four when it is reflected over the y axis the second point would be located in quadrent three and the x and y would both be negative.

Step-by-step explanation:

3 0
3 years ago
Kojo wants to be an author. To improve his writing skills, every day after school he writes 3 pages of a story he is
koban [17]

If the number of days is d and he writes 3 pages for every d, then we can say

3d = 81

3 0
3 years ago
How many complex zeros does the polynomial function have? <br><br> F(x)=2x^4 +5x^3 - x^2 +6x-1
klio [65]

Answer:

Two complex roots.

Step-by-step explanation:

F(x)=2x^4 +5x^3 - x^2 +6x-1

is a polynomial in x of degree 4.

Hence F(x) has 4 roots.  There can be 0 or 2 or 4 complex roots to this polynomial since complex roots occur in conjugate pairs.

Use remainder theorem to find the roots of the polynomial.

F(0) = -1 and F(1) = 2+5-1+6-1 = 11>0

There is a change of sign in F from 0 to 1

Thus there is a real root between 0 and 1.

Similarly by trial and error let us find other real root.

F(-3) = -1 and F(-4) = 94

SInce there is a change of sign, from -4 to -3 there exists a real root between -3 and -4.

Other two roots are complex roots since no other place F changes its sign

7 0
3 years ago
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