Answer:
et's solve for x.
5y−4x=−72y+4z
Step 1: Add -5y to both sides.
−4x+5y+−5y=−72y+4z+−5y
−4x=−77y+4z
Step 2: Divide both sides by -4.
−4x
−4
=
−77y+4z
−4
x=
77
4
y−z
Answer:
x=
77
4
y−z
Let's solve for y.
5y−4x=−72y+4z
Step 1: Add 72y to both sides.
−4x+5y+72y=−72y+4z+72y
−4x+77y=4z
Step 2: Add 4x to both sides.
−4x+77y+4x=4z+4x
77y=4x+4z
Step 3: Divide both sides by 77.
77y
77
=
4x+4z
77
y=
4
77
x+
4
77
z
Answer:
y=
4
77
x+
4
77
z
Step-by-step explanation:
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Answer:
20 Students
Step-by-step explanation:
If there is 1 chaperone for every 4 students, and there are a total of 5 chaperones on the trip, you can use this information to know that..
If there are 5 chaperones and 4 students for each chaperone, that would give you 20 students!
Answer:
b
Step-by-step explanation:
if you imply all the other ones, all the x's cancel out.
Answer: E. y(x) = 0
Step-by-step explanation:
y(x) = 0 is the only answer from the options that satisfies the differential equal y" - 4y' + 4y = 0
See:
Suppose y = e^(-2x)
Differentiate y once to have
y' = -2e^(-2x)
Differentiate the 2nd time to have
y" = 4e^(-2x)
Now substitute the values of y, y', and y" into the give differential equation, we have
4e^(-2x) - 4[-2e^(-2x)] + 4e^(-2x)
= 4e^(-2x) + 8e^(-2x) + 4e^(-2x)
= 16e^(-2x)
≠ 0
Whereas we need a solution that makes the differential equation to be equal to 0.
If you test for the remaining results, the only one that gives 0 is 0 itself, and that makes it the only possible solution from the options.
It is worth mentioning that apart from the trivial solution, 0, there is a nontrivial solution, but isn't required here.
