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lisov135 [29]
2 years ago
14

Write an equation of the line that passes through the given point and is (a) parallel and (b)

Mathematics
1 answer:
viktelen [127]2 years ago
3 0

Answer:

parallel line: y=-3x+14

perpendicular line: y=1/3x +2/3

Step-by-step explanation:

For the parallel line, use the point-slope formula to find the equation of the parallel line (since the slope is the same as the given line and the point (4,2) is given. For the perpendicular line, use the opposite reciprocal of the slope of the given line and use the point-slope formula again. The point-slope formula is Y-Y1=m(X-X1)

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-7_-4 what is the answer plz help
AlexFokin [52]

the answer is

<

because the -4 is less than -7

5 0
2 years ago
can someone help me!! Use algebraic rules of equations to predict the solution type to the system of equations. Include all of y
xz_007 [3.2K]

Answer:

x + y = 4 Equation 1

y = 2x -1 Equation 2

-2x + y = -1

x + y = 4

Subtract

You will get

- 3x = -5

Divide by -3

-3x / -3 = - 5 /-3

x = 5/3

Substitute x into equation 1

x + y = 4

x = 5/3

5/3 + y = 4

y = 4 - 5/3

y = 7/3

x = 5/3 y = 7/3

Hope this helps.

4 0
3 years ago
Please Hurry ...Which expression is equivalent to
swat32

Answer:

\huge\boxed{\sf \frac{160rs^5}{t^6}}

Step-by-step explanation:

\sf 5r^6t^4 ( \frac{4r^3s^tt^4}{2r^4st^6} ) ^5

Using rule of exponents \sf a^m/a^n = a^{m-n}

\sf 5r^6t^4 ( 2 r^{3-4} s^{2-1}t^{4-6})^5\\5r^6t^4(2r^{-1}st^{-2})^5\\5r^6t^4 * 32 r^{-5}s^5t^{-10}

Using rule of exponents \sf a^m*a^n = a^{m+n}

\sf 160 r^{6-5}s^5t^{4-10}

\sf 160 rs^5 t^{-6}

To equalize the negative sign, we'll move t to the denominator

\sf \frac{160rs^5}{t^6}

8 0
2 years ago
Help needed
alekssr [168]
A: Universe (It surrounds everything) B: Galaxy (Smaller than the universe but larger than the rest) C: Solar System D: Mars
Cant help you for number 2 though. Hope this helps :)
8 0
3 years ago
Read 2 more answers
I really need help with this FAST PLEASE!!!!!
Evgen [1.6K]
It is 1 and - 3 so b yeah
8 0
2 years ago
Read 2 more answers
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