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Question - <span>What is 400 in Expanded form ?
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We know that expanded form is a spread out way to write a number by showing the value of each individual digit that contributes<span> to make the full number.
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Lets use an example to show expanded form
Number - 4,265
= 4 x 1,000 + 2 x 100 + 6 x 10 + 5 x 1
Now lets solve for the number 400 in expanded form.
The number "4" is in the hundreds place
The number "0" is in the tenths<span> place
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<span>The number "0" is in the One's place
</span>Therefore 400 in expanded form is 400+00+0.
<span> Hope this helps </span>
Solution for f(g(5)):
The notation f(g(5)) or (f • g)(5) means that we first plug 5 into the function g(x), simplify, then plug the answer that we got to f(x). We will do this step-by-step:
Step 1: Plugging 5 to g(x)
Step 2: Plugging the answer to f(x)
ANSWER: f(g(5)) is equal to 3.
Domain:
For the function f(g(x)), we can find the domain by analyzing the domains of each individual functions separately and excluding certain values depending on the restrictions from the outermost function.
However, since both functions have all real numbers as its domain, we will not need to do any exclusion anymore.
ANSWER: The domain of the function is all real numbers.
The amount the the fed require =
20/100 x 2,000 = 400
The amount of money that Fiona's bank can lend is : $ 2,000 - $ 400
= $ 1,600
We have to present the number 41 as the sum of two squares of consecutive positive integers.
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
16 + 25 = 41
<h3>Answer: 4 and 5</h3>
Other method:
n, n + 1 - two consecutive positive integers
The equation:
n² + (n + 1)² = 41 <em>use (a + b)² = a² + 2ab + b²</em>
n² + n² + 2(n)(1) + 1² = 41
2n² + 2n + 1 = 41 <em>subtract 41 from both sides</em>
2n² + 2n - 40 = 0 <em>divide both sides by 2</em>
n² + n - 20 = 0
n² + 5n - 4n - 20= 0
n(n + 5) - 4(n + 5) = 0
(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0
n = -5 < 0 ∨ n = 4 >0
n = 4
n + 1 = 4 + 1 = 5
<h3>Answer: 4 and 5.</h3>
Answer:
-3
Step-by-step explanation:
(-5) - (-2) = (-3)
hope it helps
