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salantis [7]
3 years ago
10

Hello! Im new here and would like an answer here please!

Mathematics
1 answer:
ra1l [238]3 years ago
5 0

Answer:

You didnt post anything for someone to help you... how are we supposed to help you then?

Step-by-step explanation:

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purple

Step-by-step explanation:

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What line has slope of 5/8 and goes through the point (2,-3)
sweet-ann [11.9K]
Slope of a line passing through a point is given by: y - y1 = m(x - x1); where (x1, y1) = (2, -3) and m = 5/8.
Therefore equation of the line is y - (-3) = 5/8(x - 2)
8(y + 3) = 5x - 10
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2 years ago
C. The quotient of 3 and a number x.​
Yakvenalex [24]

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4 0
3 years ago
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Find (a) the arc length and (b) the area of a sector.
Brut [27]

Answer:

a) 23.56 ft (2 dp)

b) 58.90 ft² (2 dp)

Step-by-step explanation:

<u>Formula</u>

\textsf{Arc length}=r \theta

\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta

\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}

<u>Calculation</u>

Given:

  • \theta=\dfrac{3 \pi}{2}
  • r = 5 ft

\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 5\left(\dfrac{3 \pi}{2}\right)\\& = \dfrac{15}{2} \pi \\& = 23.56\: \sf ft\:(2\:dp)\end{aligned}

\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(5^2) \left(\dfrac{3 \pi}{2}\right)\\\\& = \dfrac{25}{2}\left(\dfrac{3 \pi}{2}\right)\\\\ & = \dfrac{75}{4} \pi \\\\& = 58.90 \: \sf ft^2\:(2\:dp)\end{aligned}

6 0
3 years ago
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