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Valentin [98]
2 years ago
11

Cristina puede mecanografiar un ensayo de 50 páginas en 8h. Si el mes pasado Cristina y Ángela juntas mecanografiaron un ensayo

del mismo tamaño en 6 horas. Cuanto tiempo le tomaría a Ángela hacerlo sola
Mathematics
1 answer:
ehidna [41]2 years ago
5 0

Cristina can type a 50 page essay in 8h. Yes, last month Cristina and Angela together typed an essay of the same size in 6 hours. How long would it take Angela to make it sun

Translated

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if a lady chargers $2.00 for gas and $3.00 per 1/2 hour of work . What is the amount of money she makes in 4 hours ?
anastassius [24]

Answer:

$32

Step-by-step explanation:

The lady charges $2.00 for gas which means over a 4 hour period we would do

4 x 2 = 8

She makes a total of 8 dollars

She also gains $3.00 per half hour of work

This means we would do 3 x 8

24

We add these values to get $32

4 0
3 years ago
Read 2 more answers
Janice’s twin sister, Janette, is also working to save money over the summer. She is in college and needs $1,000 for her books f
valina [46]

Answer:

A. It will take 13 weeks until she gets the money nd she will have $50 left!

Step-by-step explanation:

Please mark brainliest! Have a nice day!

4 0
3 years ago
What are angles that are equal called?
jonny [76]
I think the word you're looking for is congruent. Congruent angles always have the same angles.
8 0
3 years ago
If the equation x^2 - 12x - 9 = 0 is converted to the form (x - b)^2 = c and the resulting equation is (x - 6)^2 = c, what is th
Radda [10]

Answer:

Step-by-step explanation:

Identified

7 0
3 years ago
Will mark Brainlest hellpppp​
Anna007 [38]

h(-3) - h( - 2) = -  \frac{5}{  8} \\ \\

Step-by-step explanation:

\boxed{h(x) =  \frac{2 {x}^{2}  - x + 1}{3x - 2}}

h(2) =  \frac{2 {(2)}^{2}  - (2) + 1}{3(2) - 2}

h(2) =  \frac{2 {(4)}  - 2 + 1}{6 - 2}

h(2) =  \frac{ 8  - 1}{4}

h(2) =  \frac{7}{4}

h( - 3) =  \frac{2 {( - 3)}^{2}  - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) =  \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) =  \frac{18 + 4}{ - 11} \\ h( - 3) =    \frac{22}{  - 11} \\ h(-3) = -2

h( - 2) =  \frac{2 {( - 2)}^{2}  - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) =  \frac{2 (4)  +  2+ 1}{- 6 - 2} \\ h( - 2) =  \frac{8 +  3}{- 8} \\ h( - 2) =  \frac{11}{- 8}

h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8}

5 0
3 years ago
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