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3 years ago

I need help. Can someone help me please?

Mathematics

1 answer:

Katena32 [7]3 years ago

4 0

Split the shape into smaller regular shapes. Calculate the area of those then add it up.

triangle on left, base = 3 height = 8
area = 0.5(3)(8)
= 12

middle rectangle, width = 6 height = 8
area = 6(8)
= 48

small rectangle width = 2 height = 6
are = 6(2)
=12

two tiny triangles become a square side = 2
area = 2(2)
= 4

add them all up...

Total area = 12 + 48 + 12 + 4
= 76 units²

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Derman says, "I'm halfway through reading my book.if I read another 84 pages, I'll be two thirds of the way through my book." ho

Licemer1 [7]

I would say 504 basing it off of converting 2/3 into 4/6 and used sets of 84 to each be 1/6

6 0

3 years ago

Could use a little help Distance form points isn't my strong point ;-;

EastWind [94]

Answer: from up to down 9, from side to side 12

7 0

3 years ago

Read 2 more answers

Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

7 0

3 years ago

List the first 10 terms of each of these sequences.

harina [27]

Q1)
the sequence should start with 10, after that each term is calculated by subtracting 3 from the previous term.
1st term - 10
2nd term - 10 - 3 = 7
3rd term - 7 - 3 = 4
4th term - 4 - 3 = 1
5th term - 1 - 3 = -2
6th term - -2 - 3 = -5
7th term - -5 - 3 = -8
8th - -8 - 3 = -11
9th - -11 - 3 = -14
10th -14 - 3 = -17
the sequence is - 10,7,4,1,-2,-5,-8,-11,-14,-17

Q2)
the sequence whose nth term is the sum of the first n positive integers
In this we get the term by adding all the integers of the terms before that term
1st term - n = 1 no terms before this , therefore 0 + n(1) = 1
2nd term -n =2 sum of integers before - 1 + n( 2) = 3
3rd - 3+3 = 6
4th - 6+4 = 10
5th - 10 + 5 = 15
6th - 15 + 6 = 21
7th - 21 + 7 = 28
8th - 28 + 8 = 36
9th - 36 + 9 = 45
10th - 45 + 10 = 55
this is a triangular number pattern
this number pattern can be found out using ; n = (n x (n+1))/2

sequence is - 1,3,6,10,15,21,28,36,45,55

Q3)
the sequence whose nth term is 3n − 2n
general term for this sequence is 3n − 2n
to find 1st term , n = 1
substituting n = 1 in the general term
1st term - 3x1 - 2x1 = 3-2 = 1
2nd - 3x2- 2x2 = 6 - 4 = 2
3rd - 3x3 - 2x3 = 9-6 = 3
4th - 3x4 - 2x4 = 12 - 8 = 4
5th - 3x5 - 2x5 = 15 - 10 = 5
6th - 3x6 - 2x6 = 18 - 12 = 6
7th - 3x7 - 2x7 = 21 - 14 = 7
8th - 3 x8 - 2x8 = 24 - 16 = 8
9th - 3x9 - 2x9 = 27 - 18 = 9
10th - 3x10 - 2x10 = 30-20 = 10

sequence is 1,2,3,4,5,6,7,8,9,10

Q4)
the sequence whose nth term is √ n
when n=1 1st term is √1 = 1
1st term - √1 = 1
2nd term - √2 = 1.41
3rd - √3 = 1.73
4th - √4 = 2
5th - √5 = 2.23
6th- √6 = 2.44
7th - √7 = 2.65
8th- √8 = 2.82
9th - √9 = 3
10th - √10 = 3.16

The sequence is 1, 1.41, 1.73, 2, 2.23, 2.44, 2.65, 2.82, 3, 3.16

Q5)The sequence whose first two terms are 1 and 5 and each succeeding term is the sum of the two previous terms
1st term - 1
2nd term - 5
3rd term - add 1st and 2nd term (1+5) = 6
4th term - add 2nd and 3rd terms (5+6) = 11
5th - add 3rd and 4th (6+11) = 17
6th - (11+17) = 28
7th - (17 + 28) = 45
8th - 45 + 28 = 73
9th - 73 + 45 = 118
10th - 73+ 118 = 191

sequence is - 1,5,6,11,17,28,45,73,118,191

7 0

3 years ago

Read 2 more answers

What is 26.99 round to the nearest tenth

Arte-miy333 [17]

Salutations!

To round to the nearest tenth, you need know whether the number next to tenth place is greater than 5 or lesser than 5. If its greater than 5, you need to round up. If its lesser than 5, you need to round down. Now, in the number 26.99 9 is in the tenth place. The number next to 9 is greater than 5, so just add on to the ones place, making the tenth and hundredth place 0. Zero has no value so whether you add the zero or not, it does not matter.

26.99 round to the nearest tenth ≈ 27

Hope I helped (:

Have a great day!

5 0

3 years ago