I need help. Can someone help me please?
1 answer:
Split the shape into smaller regular shapes. Calculate the area of those then add it up.
triangle on left, base = 3 height = 8
area = 0.5(3)(8)
= 12
middle rectangle, width = 6 height = 8
area = 6(8)
= 48
small rectangle width = 2 height = 6
are = 6(2)
=12
two tiny triangles become a square side = 2
area = 2(2)
= 4
add them all up...
Total area = 12 + 48 + 12 + 4
= 76 units²
triangle on left, base = 3 height = 8
area = 0.5(3)(8)
= 12
middle rectangle, width = 6 height = 8
area = 6(8)
= 48
small rectangle width = 2 height = 6
are = 6(2)
=12
two tiny triangles become a square side = 2
area = 2(2)
= 4
add them all up...
Total area = 12 + 48 + 12 + 4
= 76 units²
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Answer:
The cosine function to model the height of a water particle above and below the mean water line is h = 2·cos((π/30)·t)
Step-by-step explanation:
The cosine function equation is given as follows h = d + a·cos(b(x - c))
Where:
= Amplitude
2·π/b = The period
c = The phase shift
d = The vertical shift
h = Height of the function
x = The time duration of motion of the wave, t
The given data are;
The amplitude = 2 feet
Time for the wave to pass the dock
The number of times the wave passes a point in each cycle = 2 times
Therefore;
The time for each complete cycle = 2 × 30 seconds = 60 seconds
The time for each complete cycle = Period = 2·π/b = 60
b = π/30 =
Taking the phase shift as zero, (moving wave) and the vertical shift as zero (movement about the mean water line), we have
h = 0 + 2·cos(π/30(t - 0)) = 2·cos((π/30)·t)
The cosine function is h = 2·cos((π/30)·t).