Other assumptions associated with this question are as follows:
- One person can feed on 1 hen/day for a year
- 1 hen must east 25 grasshoppers /day
- the total mass of 1000 grasshoppers is 1kg
- 600 grasshoppers are needed to feed 1 human per day
Grasshoppers is represented as Gh.
The total amount needed to feed the hen per year is:
- If expressed in Kg, then it would be 9,125/1000 which is
- = 9.125Kg/annum.
So if the farmer chose to live on grasshoppers rather than on hens, the calculation is given as follows:
- (90 kg/1 hour) x (24 hours/1 day) x (1 person/ 600 Gh)
The amount of Grasshoppers required is given as follows;
If the farmer can gather 90 Gh in one hour then,
- The total amount of Gh per day is 90 x 24 = 2,160
- the total amount of Gh available in a year is 2160 x 365 = 788,400 Gh/Year
- If 600 grasshoppers are quired to feed the human per day, then we work backward
- The total amount of Gh available in a day is 788,400/365. This is equal to 2160 Gh
- The total amount of people this can feed is given as 2,160/600
- Which is equal to 3.6 persons.
Since humans or people cannot be divided into fractions like a measure of sugar or a measure of liquid, the answer is best left to the most approximate digit with it 4 Persons.
Learn more about Trophic Levels and food availability here:
brainly.com/question/2001301
Explanation:
The frictional resistance of the various pipes are given by the
K value in the table which may be used with the formula
hf = KQ2
to relate the magnitude of head loss hf in the pipeline
to the volumetric flow rate, Q. Water is drawn at the constant flow
rates from the network at nodes C and D. The static heads
(elevation + pressure head) at nodes B, C and D are 100m, 65m
and 61m respectively above the local datum. Calculate the
discharges at C and D and the water level in reservoir A. (The
data has been added to the diagram to aid the solution)
Use no more than 3 iterations and 3 significant figures.
Answer:
Surface Mining Control and Reclamation Act
Explanation:
