Answer:
operating systems, word software, computer concepts for end users
Explanation:
operating systems allow users to interact with computer hardware and application software.
word software allows users to complete specific tasks, such as creating a document.
computer concepts for end users allows programmers to create new applications.
WAN domain which stands
for Wide Area Network and consists of the Internet and semi-private
lines.
The <span>RISKS
are: Service provider can have a major network
outage, Server can receive a DOS or DDOS attack</span>
and A FTP server can allow anonymously uploaded illegal software.
Answer:
file_name = 'orders.txt'
file_obj = open( file_name, 'r' )
lines = file_obj.read()
print(lines.upper(), end = '')
Explanation:
- Define the name of the file
.
- Use the built-in open function to open the file in read mode
.
- Use the built-in read function to read the file and assign this to lines variable.
- Finally display the lines by converting them to capital alphabets by using the built-in upper() function.
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
