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Ivenika [448]
2 years ago
14

Cell membrane present ribosomes present lysosomes present nuclear membrane present

Biology
1 answer:
aleksley [76]2 years ago
7 0

Answer:

animal

Explanation:

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The CRISPR/Cas9 system can cleave genomic DNA at sequences other than the desired target, a phenomenon referred to as off target
Deffense [45]

Answer:

The minimum length of a sgRNA sequence to avoid off target cleavage by the CRISPR/Cas system in the fly fruit genome is 14 bases

Explanation:

We are trying to use the CRISPR/Cas system to cleavage the genome of the fruit fly (which is 1.4x10^8 bp long). Also we desire the cleavage to be unique. That means we need a target sequence long enough to be able to assume it will only appear once in the genome.

First, we should think that in every position, we can find one out of four different nucleotide (A, C, T, G). So, the probability of getting a sequence of a given length "n" will be (1/4)^n (We are assuming that the probability of finding a nucleotide in the position "i", it's independent of the nucleotide we find in any other position "j").

Also, to know how many times a sequence will appear in a genome (the expected value of occurrence), we must multiply the probability of that sequence to randomly occur by the length of the genome. For our specific example, the number of occurence of a sequence of length "n" is:

nºoccurence=[(1/4)^n]*1.4*10^8

But in this case, what we want is the expected number of times the sequence will appear to be 1, and we want to obtain the length of the target sequence (n).

Given the information above, we know that:

[(1/4)^n]*1.4*10^8 =1

[(1/4)^n]=(1/1.4*10^8)=1.4*10^-8

Then, if we want to calculate n, we can use logarithms and its properties to get:

log[(1/4)^n]=log[1.4*10^-8]

n*log[(1/4)]=log[1.4*10^-8]

n=log[1.4*10^-8]/log[(1/4)] => n=13.29 approximately.

As the sequence needs to have a natural number of elements, <u>we can conclude that using a target sequence of a minimum of 14 bases with the CRISPR/Cas system in the fly fruit genome should be enough to avoid off target cleavage.</u>

3 0
3 years ago
Octopuses and squids are part of the phylum Mollusca. They both have a large brain and highly developed eyes. Which other charac
Anvisha [2.4K]
The both have 8 arms, the squid has an extra 2 tentacles though.
6 0
3 years ago
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Explain why dead or cliseased trees can serve as a food source for some<br> birds.
lianna [129]

Answer:

Dead or diseased trees can serve as a food source for some birds because there are some insects which feed on these dead trees and these insects are eaten by some birds. The body of insects is made of protein so it is a good food for birds. The insects which lived in the dead and diseased trees and feed on it are termites and bugs. Termites are also known as white ants. They feed on dead bodies of plants.

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3 years ago
What is the function of the structure below which is part of a fungus
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Gs shavevdhebhqgqgwdggwbw
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I think it would be because the lizards were able to adapt from the environment. Environment adaptation.
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