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Hatshy [7]
2 years ago
14

HELPPPPPPPPPPPPPPPPppppppppp PLEASE HELP ME

Mathematics
2 answers:
Basile [38]2 years ago
6 0

All the steps arranged in the attachment!

Oksanka [162]2 years ago
4 0

<em>C</em><em>r</em><em>e</em><em>d</em><em>i</em><em>t</em><em>s</em><em> </em><em>t</em><em>o</em><em> </em><em>X</em><em>x</em><em>B</em><em>r</em><em>a</em><em>i</em><em>n</em><em>l</em><em>y</em><em>U</em><em>s</em><em>e</em><em>r</em><em>x</em><em>X</em>

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Two numbers are in the ratio of 2 to 3. If the smaller number is 18, the larger number is___.
Tamiku [17]

Answer:

27

Step-by-step explanation:

2:3

18:?

-

2 x 9 = 18

3 x 9 = 27

4 0
3 years ago
Read 2 more answers
X2<br>2<br>ab<br>ab to<br>b<br>The diagian<br>K<br>n shows<br>rectangle. The shade<br>Find x.<br>​
Norma-Jean [14]

Answer:

x = 28 cm

Step-by-step explanation:

Given:

Area of link shaded regions = 84 cm²

Required:

The value of x (diameter of the semicircle/length of the rectangle)

Solution:

Diameter of the semicircle = 2r = x

Length of rectangle (L) = 2r = x

Radius of semicircle (r) = ½x

Width of rectangle (W) = radius of semicircle = ½x

Use 3.14 as π

Area of the link shaded regions = area of rectangle - area of semicircle

Thus:

Area of the link shaded regions = (L*W) - (½*πr²)

Plug in the values

84 = (x*½x) - (½*3.14*(½x)²)

84 = x²/2 - (1.57*x²/4)

84 = x²(½ - 1.57/4)

84 = x²(0.5 - 0.3925)

84 = x²(0.1075)

Divide both sides by 0.1075

84/0.1075 = x²

781.4 = x²

√781.4 = x

27.9535329 = x

x = 28 cm

5 0
2 years ago
A. [4 marks]
storchak [24]

The value of d is -2

Step-by-step explanation:

The nth term of the arithmetic sequence is u_{n}=u_{1}+(n-1)d , where

  • u_{1} is the first term
  • d is the common difference between each 2 consecutive terms

The nth term of the geometric sequence is u_{n}=u_{1}r^{n-1} , where

  • u_{1} is the first term
  • r is the common ratio between each two consecutive terms r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}

∵ u_{1} of an arithmetic sequence is 1

∵ The common difference is d, where d ≠ 0

∵ u_{2} , u_{3} , u_{6} are the first 3 terms of a geometric sequence

∵ u_{2} = 1 + (2 - 1)d

∴ u_{2} = 1 + d

∵ u_{3} = 1 + (3 - 1)d

∴ u_{2} = 1 + 2d

∵ u_{6} = 1 + (6 - 1)d

∴ u_{2} = 1 + 5d

∴ The first 3 terms of the geometric sequence are (1 + d) , (1 + 2d) ,

   (1 + 5d)

∵ The common ratio in the geometric sequence is r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}

∴ r=\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}

- Use cross multiplication with the equal fractions

∵ \frac{1+2d}{1+d}=\frac{1+5d}{1+2d}

∴ (1 + 2d)(1 + 2d) = (1 + d)(1 + 5d)

∴ 1 + 2d + 2d + 4d² = 1 + 5d + d + 5d²

- Add like terms in each side

∴ 1 + 4d + 4d² = 1 + 6d + 5d²

- Subtract 1 from both sides

∴ 4d + 4d² = 6d + 5d²

- Subtract 4d from both sides

∴ 4d² = 2d + 5d²

- Subtract 4d² from each side

∴ 0 = 2d + d²

- Take d as a common factor

∴ 0 = d(2 + d)

- Equate each factor by 0

∴ d = 0 but we will reject it because d ≠ 0

∴ 2 + d = 0

- Subtract 2 from both sides

∴ d = -2

The value of d is -2

Learn more:

You can learn more about the sequence in brainly.com/question/1522572

#LearnwithBrainly

7 0
3 years ago
How many ways can a group of three boys and three girls be seated in a row of six seats if boys and girls must alternate in the​
IgorC [24]

Answer:

24

Step-by-step explanation:

there are 6 seats and 3 boys, 3 girls.

First seat can be given to either boy or a girl.

So there are two ways.

If a boy is selected say, then he has to occupy 3rd and 5th only.

There are 2 ways

Now available positions are 2nd, 4th and 6th, in this girls can be arranged in 3! ways = 6

So total number of ways =

2x2x6 = 24

8 0
3 years ago
What is the area of the triangle?<br> 118 cm<br> 24 cm<br> 30 cm
Arada [10]

Answer:

360

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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