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Hatshy [7]
2 years ago
14

HELPPPPPPPPPPPPPPPPppppppppp PLEASE HELP ME

Mathematics
2 answers:
Basile [38]2 years ago
6 0

All the steps arranged in the attachment!

Oksanka [162]2 years ago
4 0

<em>C</em><em>r</em><em>e</em><em>d</em><em>i</em><em>t</em><em>s</em><em> </em><em>t</em><em>o</em><em> </em><em>X</em><em>x</em><em>B</em><em>r</em><em>a</em><em>i</em><em>n</em><em>l</em><em>y</em><em>U</em><em>s</em><em>e</em><em>r</em><em>x</em><em>X</em>

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2. Kiara baked 30 oatmeal cookies and 48 chocolate chip cookies to package in plastic containers for her friends at school. She
kolezko [41]

Answer:

you find the gcf/ greatest common factor of both numbers which is 6, so 6 plastic containers

Step-by-step explanation:

4 0
2 years ago
A farmer sells 8.9 kilograms of apples and pears at the farmer's market. 3 /4 of this weight is apples, and the rest is pears. H
aleksandrvk [35]

Answer: 2.225 kg

Step-by-step explanation:

You know that:

- The total weight the farmer sold was 8.9 kilograms.

- 3/4 of this weight is apples, and the rest is pears.

Therefore, to calculate the amount of kilograms of pears   she sold at the farmer's market (which you can call x), you need to apply the following proccedure.

Thefore, you obtain the following result:

x=8.9kg-(8.9kg*\frac{3}{4})\\x=2.225kg

4 0
3 years ago
Read 2 more answers
Pls. Help me solve with this math problem
Alchen [17]
I think this is the answer...

7 0
2 years ago
Read 2 more answers
Solve the problem. Use the Central Limit Theorem.The annual precipitation amounts in a certain mountain range are normally distr
bazaltina [42]

Answer:

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 109.0 inches, and a standard deviation of 12 inches.

This means that \mu = 109, \sigma = 12

Sample of 25.

This means that n = 25, s = \frac{12}{\sqrt{25}} = 2.4

What is the probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches?

This is the p-value of Z when X = 112. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{112 - 109}{2.4}

Z = 1.25

Z = 1.25 has a p-value of 0.8944.

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

7 0
3 years ago
Helpppp please asappp
34kurt

Answer: i may be wrong but is it 4?

5 0
2 years ago
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