5+(-4)+12.65=
5-4+12.65=
1+12.65=
13.65 is the answer
The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:

Expand the function

Reorder the terms

Factor the expression

Factor out x -1

Expand

Factorize
](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Bx%28x%20%2B%203%29%20%2B%202%28x%20%2B%203%29%5D%28x%20-%201%29)
Factor out x + 2

The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
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Point that also lies on the line is (-3, -3)
The greatest common factor is 2x^2.
the largest number that divides evenly into <span>10x^5−16x^4+4x^2
is two.
the highest degree is x^2 so the answer would be 2x^2
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