Answer:
this seems hard to do
Step-by-step explanation:
2y - x = 5
x^2 + y^2 - 25 = 0
x = 2y - 5
(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4
x = 2y - 5 , when y = 0
x = - 5
x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
1 minute = 10gal
60minutes = 10×60 gal.
1 hour = 600 gallons
Happy to help!Please tell me if you understand!
Answer:
No solution
Step-by-step explanation:
10+2x=2x+8
2x=2x-2
0≠-2
To find the missing dimension you will use the formula for finding the volume of a prism and solve for the missing dimension. In this case 2ft is how deep the pool is and you will solve for the width of the pool.
V = Bh, where B is the area of the base. In this case, use the area of a trapezoid formula.
286 = 1/2h(8 +13)2
<u>286</u> = <u>21h</u>
21 21
h = 13.6
The width of the wading pool is approximately 13.6 feet.
