H = -16t² + 64t + 80 (:16)
H = -t² + 4t + 5
/\ = b²-4ac
/\ = 4²-4.(-1).5
/\ = 16+20
/\ = 36
Yv = -/\ / 4a
Yv = -36/4.(-1)
Yv = -36/-4
Yv = 9
Answer:
x=16 y=38
Step-by-step explanation:
x+y=54.......equation 1
x=y-22........ equation 2
substitute
y-22+y=54
2y-22=54
2y=54+22
2y=76
y=76/2
y=38''
x=y-22
x=38-22
x=16''
<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
Answer:
It should be 0.012566 rounded
Step-by-step explanation:
Answer:
1 / q^30.
Step-by-step explanation:
[(p^2)(q^5)]^-4 * [(p^-4)(q^5)]^-2
Using the law (a^b)^c = a^bc :-
= p^-8 * q^-20 * p^8 * q^-10
= p^(-8+8) * q^(-20-10)
= p^0 * q^-30
= 1 * q^-30.
= 1 / q^30.
