A. c + 7 ≤ 3
c ≤ -4
a = 2
b. c - 3 > 1
c > 4
b = 3
c. c - 7 < 3
c < 10
c = 2
Answer:
3x +15y +7z = 46
Step-by-step explanation:
The cross product of v = <2, 1, -3> and PQ = <-5, 1, 0> is <3, 15, 7>, the normal vector of the plane of interest. That plane contains P and Q, so the constant in the plane's equation will be ...
<3, 15, 7> · <3, 2, 1> = 46
The desired equation is ...
3x +15y +7z = 46
Answer: -6
Step-by-step explanation:
Hello!
The answer is B. 2.777.
I hope this helps :))
Its 7.
Have a good day :)
